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A copper pipe (k = 350 W/m K) having inner diameter of 1.75 cm and 2.0 cm outside diameter conveys water and the oil flows through the annular passage between this pipe and a steel pipe. On the water side, the film coefficient is 4600 W/m2 K and the fouling factor is 0.00034 m2 K/W. The corresponding values for the oil side are 1200 W/mK and 0.00086 m2K/W. Estimate the overall heat transfer coefficient between the oil and water
  • a)
    235.16 W/mK
  • b)
    335.16 W/mK
  • c)
    435.16 W/mK
  • d)
    535.16 W/mK
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A copper pipe (k = 350 W/m K) having inner diameter of 1.75 cm and 2.0...
A fouling factor represents the reciprocal of the scale coefficient i.e. heat transfer.
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A copper pipe (k = 350 W/m K) having inner diameter of 1.75 cm and 2.0...
Given data:
- Inner diameter of copper pipe, D_i = 1.75 cm
- Outer diameter of copper pipe, D_o = 2.0 cm
- Thermal conductivity of copper, k_c = 350 W/m K
- Film coefficient on water side, h_w = 4600 W/m2K
- Fouling factor on water side, R_f,w = 0.00034 m2K/W
- Film coefficient on oil side, h_o = 1200 W/m2K
- Fouling factor on oil side, R_f,o = 0.00086 m2K/W

Assumptions:
- Steady-state heat transfer
- Negligible thickness of copper pipe wall
- Uniform inner and outer surface temperatures
- Negligible axial conduction

Overall heat transfer coefficient, U, can be calculated using the following formula:

1/U = (1/hi) + (Rfi) + (Do/Di)(Rfo) + (Do/Di)(1/ho)

where,
- hi is the convective heat transfer coefficient on the inside surface of copper pipe
- Rfi is the fouling resistance on the inside surface of copper pipe
- Rfo is the fouling resistance on the outside surface of copper pipe
- ho is the convective heat transfer coefficient on the outside surface of steel pipe

Calculation steps:
1. Calculate the inside surface area of copper pipe:
A_i = π D_i L, where L is the length of the pipe
2. Calculate the outside surface area of copper pipe:
A_o = π D_o L, where L is the length of the pipe
3. Calculate the perimeter of annular passage:
P = π (D_o - D_i)
4. Calculate the hydraulic diameter of annular passage:
D_h = (4 A_o) / P
5. Calculate the Reynolds number for oil flow:
Re_o = (ρ_o V D_h) / μ_o, where V is the velocity of oil flow, ρ_o is the density of oil, and μ_o is the viscosity of oil
6. Calculate the Nusselt number for oil side:
Nu_o = (0.36 + (0.52 / (1 + 0.027 / D_h^0.8))) * Re_o^0.6 * Pr_o^0.4, where Pr_o is the Prandtl number of oil
7. Calculate the convective heat transfer coefficient on oil side:
h_o = (Nu_o k_o) / D_h, where k_o is the thermal conductivity of steel
8. Calculate the fouling resistance on oil side:
R_f,o = (t_f,o / k_o) * (1 / A_o), where t_f,o is the fouling thickness on oil side
9. Calculate the Reynolds number for water flow:
Re_w = (ρ_w V D_i) / μ_w, where V is the velocity of water flow, ρ_w is the density of water, and μ_w is the viscosity of water
10. Calculate the Prandtl number for water:
Pr_w = (C_p,w μ_w) / k_w, where C_p,w is the specific heat of water, and k_w is the thermal conductivity of water
11. Calculate the Nusselt number for water side:
Nu_w = 0.023 * (Re
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A copper pipe (k = 350 W/m K) having inner diameter of 1.75 cm and 2.0 cm outside diameter conveys water and the oil flows through the annular passage between this pipe and a steel pipe. On the water side, the film coefficient is 4600 W/m2K and the fouling factor is 0.00034 m2K/W. The corresponding values for the oil side are 1200 W/m2K and 0.00086 m2K/W. Estimate the overall heat transfer coefficient between the oil and watera)235.16 W/m2Kb)335.16 W/m2Kc)435.16 W/m2Kd)535.16 W/m2KCorrect answer is option 'C'. Can you explain this answer?
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A copper pipe (k = 350 W/m K) having inner diameter of 1.75 cm and 2.0 cm outside diameter conveys water and the oil flows through the annular passage between this pipe and a steel pipe. On the water side, the film coefficient is 4600 W/m2K and the fouling factor is 0.00034 m2K/W. The corresponding values for the oil side are 1200 W/m2K and 0.00086 m2K/W. Estimate the overall heat transfer coefficient between the oil and watera)235.16 W/m2Kb)335.16 W/m2Kc)435.16 W/m2Kd)535.16 W/m2KCorrect answer is option 'C'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A copper pipe (k = 350 W/m K) having inner diameter of 1.75 cm and 2.0 cm outside diameter conveys water and the oil flows through the annular passage between this pipe and a steel pipe. On the water side, the film coefficient is 4600 W/m2K and the fouling factor is 0.00034 m2K/W. The corresponding values for the oil side are 1200 W/m2K and 0.00086 m2K/W. Estimate the overall heat transfer coefficient between the oil and watera)235.16 W/m2Kb)335.16 W/m2Kc)435.16 W/m2Kd)535.16 W/m2KCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper pipe (k = 350 W/m K) having inner diameter of 1.75 cm and 2.0 cm outside diameter conveys water and the oil flows through the annular passage between this pipe and a steel pipe. On the water side, the film coefficient is 4600 W/m2K and the fouling factor is 0.00034 m2K/W. The corresponding values for the oil side are 1200 W/m2K and 0.00086 m2K/W. Estimate the overall heat transfer coefficient between the oil and watera)235.16 W/m2Kb)335.16 W/m2Kc)435.16 W/m2Kd)535.16 W/m2KCorrect answer is option 'C'. Can you explain this answer?.
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