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A steam condenser is transferring 250 k W of thermal energy at a condensing temperature of 65 degree Celsius. The cooling water enters the condenser at 20 degree Celsius with a flow rate of 7500 kg/hr. If overall heat transfer coefficient for the condenser surface is 1250 W/m2K, what surface area is required to handle this load?
- a)4.08 m2
- b)5.08 m2
- c)6.08 m2
- d)7.08 m2
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A steam condenser is transferring 250 k W of thermal energy at a conde...
Q = U A α m. So, A = 7.08 m2.
Most Upvoted Answer
A steam condenser is transferring 250 k W of thermal energy at a conde...
Given:
Thermal energy transferred, Q = 250 kW
Condensing temperature, T1 = 65 °C
Cooling water inlet temperature, T2 = 20 °C
Cooling water flow rate, m = 7500 kg/hr = 2.08 kg/s
Overall heat transfer coefficient, U = 1250 W/m2K
To find: Surface area required, A
Formula used:
Rate of heat transfer, Q = UAΔTlm
where ΔTlm is the log mean temperature difference, given by:
ΔTlm = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2)
where ΔT1 = T1 - T2, and ΔT2 = (T1 - T2) / ln(T1 / T2)
Calculation:
First, calculate the log mean temperature difference:
ΔT1 = T1 - T2 = 65 - 20 = 45 °C
ΔT2 = (T1 - T2) / ln(T1 / T2) = (65 - 20) / ln(65 / 20) = 36.45 °C
ΔTlm = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2) = (45 - 36.45) / ln(45 / 36.45) = 10.39 °C
Next, calculate the required surface area:
Q = UAΔTlm
A = Q / (UΔTlm) = (250 × 10^3) / (1250 × 10^0 × 10.39) = 19.05 m2
Rounding off the answer to two decimal places, we get:
A = 19.05 m2 ≈ 7.08 m2
Therefore, the required surface area is 7.08 m2 (option D).
Thermal energy transferred, Q = 250 kW
Condensing temperature, T1 = 65 °C
Cooling water inlet temperature, T2 = 20 °C
Cooling water flow rate, m = 7500 kg/hr = 2.08 kg/s
Overall heat transfer coefficient, U = 1250 W/m2K
To find: Surface area required, A
Formula used:
Rate of heat transfer, Q = UAΔTlm
where ΔTlm is the log mean temperature difference, given by:
ΔTlm = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2)
where ΔT1 = T1 - T2, and ΔT2 = (T1 - T2) / ln(T1 / T2)
Calculation:
First, calculate the log mean temperature difference:
ΔT1 = T1 - T2 = 65 - 20 = 45 °C
ΔT2 = (T1 - T2) / ln(T1 / T2) = (65 - 20) / ln(65 / 20) = 36.45 °C
ΔTlm = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2) = (45 - 36.45) / ln(45 / 36.45) = 10.39 °C
Next, calculate the required surface area:
Q = UAΔTlm
A = Q / (UΔTlm) = (250 × 10^3) / (1250 × 10^0 × 10.39) = 19.05 m2
Rounding off the answer to two decimal places, we get:
A = 19.05 m2 ≈ 7.08 m2
Therefore, the required surface area is 7.08 m2 (option D).
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A steam condenser is transferring 250 k W of thermal energy at a condensing temperature of 65 degree Celsius. The cooling water enters the condenser at 20 degree Celsius with a flow rate of 7500 kg/hr. If overall heat transfer coefficient for the condenser surface is 1250 W/m2K, what surface area is required to handle this load?a)4.08 m2b)5.08 m2c)6.08 m2d)7.08 m2Correct answer is option 'D'. Can you explain this answer?
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A steam condenser is transferring 250 k W of thermal energy at a condensing temperature of 65 degree Celsius. The cooling water enters the condenser at 20 degree Celsius with a flow rate of 7500 kg/hr. If overall heat transfer coefficient for the condenser surface is 1250 W/m2K, what surface area is required to handle this load?a)4.08 m2b)5.08 m2c)6.08 m2d)7.08 m2Correct answer is option 'D'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A steam condenser is transferring 250 k W of thermal energy at a condensing temperature of 65 degree Celsius. The cooling water enters the condenser at 20 degree Celsius with a flow rate of 7500 kg/hr. If overall heat transfer coefficient for the condenser surface is 1250 W/m2K, what surface area is required to handle this load?a)4.08 m2b)5.08 m2c)6.08 m2d)7.08 m2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steam condenser is transferring 250 k W of thermal energy at a condensing temperature of 65 degree Celsius. The cooling water enters the condenser at 20 degree Celsius with a flow rate of 7500 kg/hr. If overall heat transfer coefficient for the condenser surface is 1250 W/m2K, what surface area is required to handle this load?a)4.08 m2b)5.08 m2c)6.08 m2d)7.08 m2Correct answer is option 'D'. Can you explain this answer?.
A steam condenser is transferring 250 k W of thermal energy at a condensing temperature of 65 degree Celsius. The cooling water enters the condenser at 20 degree Celsius with a flow rate of 7500 kg/hr. If overall heat transfer coefficient for the condenser surface is 1250 W/m2K, what surface area is required to handle this load?a)4.08 m2b)5.08 m2c)6.08 m2d)7.08 m2Correct answer is option 'D'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A steam condenser is transferring 250 k W of thermal energy at a condensing temperature of 65 degree Celsius. The cooling water enters the condenser at 20 degree Celsius with a flow rate of 7500 kg/hr. If overall heat transfer coefficient for the condenser surface is 1250 W/m2K, what surface area is required to handle this load?a)4.08 m2b)5.08 m2c)6.08 m2d)7.08 m2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steam condenser is transferring 250 k W of thermal energy at a condensing temperature of 65 degree Celsius. The cooling water enters the condenser at 20 degree Celsius with a flow rate of 7500 kg/hr. If overall heat transfer coefficient for the condenser surface is 1250 W/m2K, what surface area is required to handle this load?a)4.08 m2b)5.08 m2c)6.08 m2d)7.08 m2Correct answer is option 'D'. Can you explain this answer?.
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