The complex ion [Co(NH3)6]3+ is formed by sp3d2 hybridisation. Hence t...
According to VSEPR theory, a molecule with six bond pairs must be octahedral.
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The complex ion [Co(NH3)6]3+ is formed by sp3d2 hybridisation. Hence t...
Since the hybridisation of central metal tin [Co(NH3)6]3+complex ion is sp3d2 and coordination number of Co3+ is 6. So, its geometry is octahedral
The complex ion [Co(NH3)6]3+ is formed by sp3d2 hybridisation. Hence t...
Octahedral Geometry
- The complex ion [Co(NH3)6]3+ contains a central cobalt ion (Co3+) surrounded by six ammonia ligands (NH3).
- To determine the geometry of the complex ion, we need to consider the hybridization of the central atom, cobalt.
- The electronic configuration of cobalt is [Ar] 3d7 4s2. In the complex ion, cobalt loses three electrons to form Co3+.
- The hybridization of the central atom is determined by the number of electron pairs around it. In this case, there are six ammonia ligands, each contributing a lone pair of electrons to the cobalt ion.
- The hybridization of the central cobalt ion is sp3d2, which means that there are six hybrid orbitals formed by combining one s, three p, and two d orbitals.
- The six ammonia ligands will then bond with these six hybrid orbitals of cobalt.
- The shape of the hybrid orbitals is octahedral, which means that the complex ion will have an octahedral geometry.
- In an octahedral geometry, the six ligands are arranged symmetrically around the central atom in a three-dimensional shape that resembles two square pyramids, one stacked on top of the other.
- The bond angles in an octahedral complex are approximately 90 degrees between the ligands in the same plane and 180 degrees between the ligands in different planes.
- Therefore, the correct answer is option 'A' - Octahedral geometry.
In summary, the complex ion [Co(NH3)6]3+ is formed by sp3d2 hybridization of the central cobalt ion, resulting in an octahedral geometry in which the six ammonia ligands are arranged symmetrically around the cobalt ion.