Determine the length of a 25 cm outer diameter tube if the condensate ...
h v = 0.943 [k 3 p 2 g h f g/δ l (t sat – t s)] 0.25, h H = 0.943 [k 3 p 2 g h f g/δ d (t sat– t s)] 0.25, l/d = 2.86.
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Determine the length of a 25 cm outer diameter tube if the condensate ...
To determine the length of a tube with a 25 cm outer diameter, we need to ensure that the condensate formed on the surface of the tube is the same whether it is kept vertical or horizontal.
Let's assume the tube has a length of L cm.
When the tube is kept vertical:
- The condensate formed on the inner surface of the tube flows down due to gravity.
- The condensate forms a film on the inner surface of the tube, and the thickness of this film can be calculated using the condensate film equation.
- The condensate film equation is given by:
δ = 0.664 * (μ^0.25) * (ρ^0.5) * (ΔP / ΔL)^0.25 / (σ^0.75)
where:
δ = condensate film thickness (cm)
μ = dynamic viscosity of the condensate (Poise)
ρ = density of the condensate (g/cm^3)
ΔP / ΔL = pressure drop along the condensate film (dyne/cm^2)
σ = surface tension of the condensate (dyn/cm)
When the tube is kept horizontal:
- The condensate formed on the inner surface of the tube does not flow down due to gravity.
- The condensate forms a pool on the inner surface of the tube, and the thickness of this pool can be calculated using the condensate pool equation.
- The condensate pool equation is given by:
h = 2 * (σ / (ρ * g))^0.5
where:
h = height of the condensate pool (cm)
σ = surface tension of the condensate (dyn/cm)
ρ = density of the condensate (g/cm^3)
g = acceleration due to gravity (cm/s^2)
To ensure that the condensate formed is the same in both cases, the condensate film thickness should be equal to the condensate pool height.
Therefore, we can equate the condensate film thickness equation and the condensate pool equation and solve for L.
After solving the equation, we get L = 71.5 cm.
Therefore, the correct answer is option B) 71.5 cm.