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The volume of concentrated h2so4 whose density is 1.84 and which contains 98 percent by weight of h2so4 that must be diluted with water to prepare 100 cm3 of acid solution whose density is 1.14 and which contains 20 wt percent h2so4?
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The volume of concentrated h2so4 whose density is 1.84 and which conta...
Method to Solve :

Apparently, you want us to do your homework for you. Below is the solution to your question. Do know that this solution is useless to you unless you understand each step and why it is taken. So while I give you the solution to the question, it will be up to you to study this answer carefully and make sure you understand it.

To start of with, we will need to fix the question itself as it contains a rather big error. The density of any substance is given in g/cm^3. Not in g/mol as that would be the molecular weight. So the density is 1.84 g/cm^3 (=1.84 g/mL).

The answer:

0.2M = 0.2 mole/L

Therefore, 0.5L * 0.2M = 0.1 mole of H2SO4 required.

The molar mass of H2SO4 is 98.079 g/mole (see periodic table or google).

Therefore, 98.079 g/mole * 0.1 mole = 9.8079 g

9.8079 g/ 1.84 g/cm^3 = 5.33038 cm^3 (=5.33038 mL)

The purity of your substance is 96%, therefore you will actually need:

5.33038*(1/0.96) = 5.55248 mL.

The required precision in your answer is 3 digits (due to the precision of 500 mL).

Therefore, the answer is 5.55 mL of acid and (500–5.55 =) 494 mL of water.
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The volume of concentrated h2so4 whose density is 1.84 and which conta...

Calculating the Volume of Concentrated H2SO4:

- Given data:
- Density of concentrated H2SO4 = 1.84 g/cm3
- Concentration of H2SO4 in concentrated solution = 98% by weight

- Let V1 be the volume of concentrated H2SO4 needed.

- Using the formula:
Mass = Volume x Density
Mass of H2SO4 in V1 = V1 x 1.84 x 0.98 (since the solution is 98% H2SO4)

- Mass of H2SO4 required in the final solution:
Mass of H2SO4 in final solution = 100 x 1.14 x 0.20

- Equating the masses:
V1 x 1.84 x 0.98 = 100 x 1.14 x 0.20

- Solving for V1:
V1 = (100 x 1.14 x 0.20) / (1.84 x 0.98)

- Calculate the value of V1.

Diluting the Concentrated H2SO4:

- Let V2 be the volume of water added to dilute the solution.
- The total volume of the final solution = V1 + V2 = 100 cm3

- Calculate the volume of water (V2) added to the concentrated H2SO4 to prepare the final solution.

Explanation:

- The initial step involves determining the volume of concentrated H2SO4 required based on the given concentration and density.
- The final step is to calculate the volume of water needed to dilute the concentrated solution to achieve the desired concentration and volume of the final solution.
- By following these calculations, the appropriate volumes of concentrated H2SO4 and water can be mixed to prepare the acid solution with the specified characteristics.
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The volume of concentrated h2so4 whose density is 1.84 and which contains 98 percent by weight of h2so4 that must be diluted with water to prepare 100 cm3 of acid solution whose density is 1.14 and which contains 20 wt percent h2so4?
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The volume of concentrated h2so4 whose density is 1.84 and which contains 98 percent by weight of h2so4 that must be diluted with water to prepare 100 cm3 of acid solution whose density is 1.14 and which contains 20 wt percent h2so4? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The volume of concentrated h2so4 whose density is 1.84 and which contains 98 percent by weight of h2so4 that must be diluted with water to prepare 100 cm3 of acid solution whose density is 1.14 and which contains 20 wt percent h2so4? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The volume of concentrated h2so4 whose density is 1.84 and which contains 98 percent by weight of h2so4 that must be diluted with water to prepare 100 cm3 of acid solution whose density is 1.14 and which contains 20 wt percent h2so4?.
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