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The output voltage of a battery drops from 100 V with zero load current to 80 V when load current is 2 A. The internal resistance of the battery is
- a)10 Ω
- b)20 Ω
- c)40 Ω
- d)50 Ω
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The output voltage of a battery drops from 100 V with zero load curren...
Let the internal resistance of the battery is r.
When load current is zero, output voltage = 100 V
Battery voltage = 100 V
When load current is 2 A, the output voltage is 80 V
⇒ 100 – 2r = 80
⇒ r = 10 Ω
When load current is zero, output voltage = 100 V
Battery voltage = 100 V
When load current is 2 A, the output voltage is 80 V
⇒ 100 – 2r = 80
⇒ r = 10 Ω
Most Upvoted Answer
The output voltage of a battery drops from 100 V with zero load curren...
Understanding Battery Voltage Drop
When a battery is connected to a load, the output voltage can drop due to the internal resistance of the battery. In this case, we have the following data:
- Open-circuit voltage (Voc) = 100 V (when no load is connected)
- Load voltage (Vl) = 80 V (when a load of 2 A is connected)
Calculating Internal Resistance
To find the internal resistance (r) of the battery, we can use Ohm's Law and the following formula:
\[ V_{drop} = I \times r \]
Where:
- \( V_{drop} \) = Voltage drop across the internal resistance
- I = Load current
The voltage drop can be calculated as:
\[ V_{drop} = V_{oc} - V_{l} \]
Substituting the values:
\[ V_{drop} = 100 V - 80 V = 20 V \]
Now, substituting in the formula:
\[ 20 V = 2 A \times r \]
Solving for r:
\[ r = \frac{20 V}{2 A} = 10 \Omega \]
Conclusion
Thus, the internal resistance of the battery is 10 Ω, confirming that the correct answer is option 'A'.
By understanding the relationship between voltage, current, and internal resistance, we can effectively analyze battery performance under load conditions.
When a battery is connected to a load, the output voltage can drop due to the internal resistance of the battery. In this case, we have the following data:
- Open-circuit voltage (Voc) = 100 V (when no load is connected)
- Load voltage (Vl) = 80 V (when a load of 2 A is connected)
Calculating Internal Resistance
To find the internal resistance (r) of the battery, we can use Ohm's Law and the following formula:
\[ V_{drop} = I \times r \]
Where:
- \( V_{drop} \) = Voltage drop across the internal resistance
- I = Load current
The voltage drop can be calculated as:
\[ V_{drop} = V_{oc} - V_{l} \]
Substituting the values:
\[ V_{drop} = 100 V - 80 V = 20 V \]
Now, substituting in the formula:
\[ 20 V = 2 A \times r \]
Solving for r:
\[ r = \frac{20 V}{2 A} = 10 \Omega \]
Conclusion
Thus, the internal resistance of the battery is 10 Ω, confirming that the correct answer is option 'A'.
By understanding the relationship between voltage, current, and internal resistance, we can effectively analyze battery performance under load conditions.
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The output voltage of a battery drops from 100 V with zero load current to 80 V when load current is 2 A. The internal resistance of the battery isa)10 Ωb)20 Ωc)40 Ωd)50 ΩCorrect answer is option 'A'. Can you explain this answer?
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