If -5 is a root of the quadratic equation 2 X square bx - 15 is equa...
If -5 is a root of the quadratic equation 2 X square bx - 15 is equa...
Quadratic Equation 1: 2x² + bx - 15 = 0
Quadratic Equation 2: px² + px + 3 = 0
Given Information:
- -5 is a root of the quadratic equation 2x² + bx - 15 = 0
- The equation px² + px + 3 = 0 has equal roots
Analysis:
To find the values of 'b' and 'p', we will use the given information and apply the properties of quadratic equations.
Finding the Value of 'b':
Since -5 is a root of the equation 2x² + bx - 15 = 0, we can substitute x = -5 into the equation and solve for 'b'.
2(-5)² + b(-5) - 15 = 0
50 - 5b - 15 = 0
-5b + 35 = 0
-5b = -35
b = 7
Therefore, the value of 'b' is 7.
Finding the Value of 'p':
The equation px² + px + 3 = 0 has equal roots. This means the discriminant of this equation is zero.
The discriminant (D) of a quadratic equation ax² + bx + c = 0 is given by the formula:
D = b² - 4ac
In our equation px² + px + 3 = 0, we have a = p, b = p, and c = 3. Substituting these values into the formula for the discriminant, we have:
D = p² - 4p(3)
D = p² - 12p
Since the equation has equal roots, the discriminant is zero.
D = 0
p² - 12p = 0
p(p - 12) = 0
This equation will have equal roots when either p = 0 or p - 12 = 0.
If p = 0, the equation becomes 0x² + 0x + 3 = 0, which does not have equal roots.
If p - 12 = 0, then p = 12.
Therefore, the value of 'p' is 12.
Conclusion:
The values of 'b' and 'p' that satisfy the given conditions are b = 7 and p = 12.
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