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A conveyor belt is moving at a constant speed of 2m/s. A box is gently dropped on it. The coefficient of friction between them is µ = 0.5. The distance that the box will move relative to belt before coming to rest on it taking g = 10 ms–2, is [2011M]
  • a)
    1.2 m
  • b)
    0.6 m
  • c)
    zero
  • d)
    0.4 m
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A conveyor belt is moving at a constant speed of 2m/s. A box is gently...
Frictional force on the box f = μmg
∴ Acceleration in the box
⇒ distance = 0.4 m
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A conveyor belt is moving at a constant speed of 2m/s. A box is gently dropped on it. The coefficient of friction between them is µ = 0.5. The distance that the box will move relative to belt before coming to rest on it taking g = 10 ms–2, is [2011M]a)1.2 mb)0.6 mc)zerod)0.4 mCorrect answer is option 'D'. Can you explain this answer?
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