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A pitot tube (Coefficient=1) is used to measure the velocity of air of mass density 1.2kg/m^3. If the head difference in a vertical U-tube filled with water is 12 mm, then the velocity of air (in m/s) will be ?
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A pitot tube (Coefficient=1) is used to measure the velocity of air of...
Calculation of Air Velocity using Pitot Tube

Given:

Coefficient of Pitot Tube (C) = 1

Density of air (ρ) = 1.2 kg/m³

Head difference (h) = 12 mm (0.012 m)

Formula:

Velocity of air (V) = √(2gh/ρ)

where g = acceleration due to gravity = 9.81 m/s²

Calculation:

Velocity of air (V) = √(2gh/ρ)

V = √(2 × 9.81 × 0.012 / 1.2) = 4.92 m/s

Therefore, the velocity of air is 4.92 m/s.

Explanation:

A pitot tube is used to measure the velocity of fluid (in this case, air) by converting the kinetic energy of the fluid into potential energy. The tube has two openings, one facing the fluid flow (total pressure) and the other perpendicular to the flow (static pressure). The difference in pressure is measured and used to determine the velocity of the fluid.

In this problem, the head difference in a vertical U-tube filled with water is given. This difference in pressure can be converted into velocity using the above formula. The coefficient of the pitot tube is given as 1, which means that the tube is efficient in converting the kinetic energy of the fluid into potential energy.

By substituting the given values into the formula, we get the velocity of air as 4.92 m/s.
Community Answer
A pitot tube (Coefficient=1) is used to measure the velocity of air of...
¶ be the symbol of density
¶air=1.2
¶water=1000
x=0.012

h = {[¶a/¶w]-1}x0.012
h= 9.988

v= √(2gh)
v= √(2*9.81*9.988)
v= 13.99
v~14

so the velocity of air is 14m/s.
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A pitot tube (Coefficient=1) is used to measure the velocity of air of mass density 1.2kg/m^3. If the head difference in a vertical U-tube filled with water is 12 mm, then the velocity of air (in m/s) will be ?
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