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How many complex additions are performed in computing the N-point DFT of a sequence using divide-and-conquer method if N=LM?
  • a)
    N(L+M+2)
  • b)
    N(L+M-2)
  • c)
    N(L+M-1)
  • d)
    N(L+M+1)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
How many complex additions are performed in computing the N-point DFT ...
Explanation: The expression for N point DFT is given as
The first step involves L DFTs, each of M points. Hence this step requires LM(M-1) complex additions, second step do not require any additions and finally third step requires ML(L-1) complex additions. So, Total number of complex additions= N(L+M-2).
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