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A solid sphere of radius R is placed on a smooth horizontal surface. A horizontal force F is applied at height h from the lowest point. For the maximum acceleration of the centre of mass, [2002]
- a)h = R
- b)h = 2R
- c)h = 0
- d)The acceleration will be same whatever h may be
Correct answer is option 'D'. Can you explain this answer?
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A solid sphere of radius R is placed on a smooth horizontal surface. A...
As friction is absent at the point of contact,
Accelerati on 
It is independent of h
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A solid sphere of radius R is placed on a smooth horizontal surface. A...
Analysis:
To determine the maximum acceleration of the center of mass of the solid sphere, we need to consider the forces acting on the sphere when the horizontal force F is applied at height h from the lowest point.
Force Analysis:
- When the force F is applied at a height h from the lowest point, two forces act on the sphere: the gravitational force mg acting at the center of mass and the applied horizontal force F.
- The force of friction between the sphere and the surface acts in the opposite direction of the applied force F.
Conditions for Maximum Acceleration:
- The maximum acceleration of the center of mass occurs when the force of friction is at its maximum value. This happens when the sphere is on the verge of slipping.
- At this point, the frictional force equals the maximum static friction force, given by μsN, where μs is the coefficient of static friction and N is the normal force.
- The normal force N is equal to the weight of the sphere mg acting at the center of mass.
- Therefore, the maximum acceleration is independent of the height h at which the force is applied. The acceleration will be the same regardless of the value of h.
Conclusion:
- The correct option is D) The acceleration will be the same regardless of the value of h.
- This is because the maximum acceleration occurs when the sphere is on the verge of slipping, and at this point, the height at which the force is applied does not affect the acceleration of the center of mass.
To determine the maximum acceleration of the center of mass of the solid sphere, we need to consider the forces acting on the sphere when the horizontal force F is applied at height h from the lowest point.
Force Analysis:
- When the force F is applied at a height h from the lowest point, two forces act on the sphere: the gravitational force mg acting at the center of mass and the applied horizontal force F.
- The force of friction between the sphere and the surface acts in the opposite direction of the applied force F.
Conditions for Maximum Acceleration:
- The maximum acceleration of the center of mass occurs when the force of friction is at its maximum value. This happens when the sphere is on the verge of slipping.
- At this point, the frictional force equals the maximum static friction force, given by μsN, where μs is the coefficient of static friction and N is the normal force.
- The normal force N is equal to the weight of the sphere mg acting at the center of mass.
- Therefore, the maximum acceleration is independent of the height h at which the force is applied. The acceleration will be the same regardless of the value of h.
Conclusion:
- The correct option is D) The acceleration will be the same regardless of the value of h.
- This is because the maximum acceleration occurs when the sphere is on the verge of slipping, and at this point, the height at which the force is applied does not affect the acceleration of the center of mass.
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A solid sphere of radius R is placed on a smooth horizontal surface. A horizontal force F is applied at height h from the lowest point. For the maximum acceleration of the centre of mass, [2002]a)h = Rb)h = 2Rc)h = 0d)The acceleration will be same whatever h may beCorrect answer is option 'D'. Can you explain this answer?
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A solid sphere of radius R is placed on a smooth horizontal surface. A horizontal force F is applied at height h from the lowest point. For the maximum acceleration of the centre of mass, [2002]a)h = Rb)h = 2Rc)h = 0d)The acceleration will be same whatever h may beCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solid sphere of radius R is placed on a smooth horizontal surface. A horizontal force F is applied at height h from the lowest point. For the maximum acceleration of the centre of mass, [2002]a)h = Rb)h = 2Rc)h = 0d)The acceleration will be same whatever h may beCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid sphere of radius R is placed on a smooth horizontal surface. A horizontal force F is applied at height h from the lowest point. For the maximum acceleration of the centre of mass, [2002]a)h = Rb)h = 2Rc)h = 0d)The acceleration will be same whatever h may beCorrect answer is option 'D'. Can you explain this answer?.
A solid sphere of radius R is placed on a smooth horizontal surface. A horizontal force F is applied at height h from the lowest point. For the maximum acceleration of the centre of mass, [2002]a)h = Rb)h = 2Rc)h = 0d)The acceleration will be same whatever h may beCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solid sphere of radius R is placed on a smooth horizontal surface. A horizontal force F is applied at height h from the lowest point. For the maximum acceleration of the centre of mass, [2002]a)h = Rb)h = 2Rc)h = 0d)The acceleration will be same whatever h may beCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid sphere of radius R is placed on a smooth horizontal surface. A horizontal force F is applied at height h from the lowest point. For the maximum acceleration of the centre of mass, [2002]a)h = Rb)h = 2Rc)h = 0d)The acceleration will be same whatever h may beCorrect answer is option 'D'. Can you explain this answer?.
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