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If the roots of the quadratic equation Kx2+3x+2=0 are real and unequal, which of the following is true for K?
  • a)
    K>9/8
  • b)
    K<9/8
  • c)
    K<−9/8
  • d)
    K>8/9
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If the roots of the quadratic equationKx2+3x+2=0are real and unequal, ...
Roots are real and unequal, if D=b2−4ac>0 So, for equation kx2+3x+2=0 roots  will be real and unequal, it D=(3)2−4×2×K>0 i.e., 9−8K>0 ⇒ K > 9/8
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Most Upvoted Answer
If the roots of the quadratic equationKx2+3x+2=0are real and unequal, ...
If the roots of the quadratic equation Kx^2 + 3x + 2 = 0 are real and unequal, then the discriminant of the quadratic equation must be positive. The discriminant is given by the formula b^2 - 4ac, where a, b, and c are the coefficients of the quadratic equation.

In this case, a = K, b = 3, and c = 2. So the discriminant is:

(3)^2 - 4(K)(2) = 9 - 8K.

For the roots to be real and unequal, the discriminant must be positive:

9 - 8K > 0.

Simplifying this inequality, we get:

-8K > -9.

Dividing both sides by -8 (and reversing the inequality because we are dividing by a negative number), we get:

K < />

Therefore, the correct answer is:

a) K < 9/8.="" />
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If the roots of the quadratic equationKx2+3x+2=0are real and unequal, which of the following is true for K?a)K>9/8b)K<9/8c)K<−9/8d)K>8/9Correct answer is option 'B'. Can you explain this answer?
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