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The monochromatic emissivity € of a diffuse surface at 1600 K varies with wavelength in the following manner
€ = 0.4 for 0 < λ < 2
= 0.8 for 2 < λ < 5
Determine the total emissivity
  • a)
    0.5558
  • b)
    0.5568
  • c)
    0.5578
  • d)
    0.5588
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The monochromatic emissivity € of a diffuse surface at 1600 K var...
Total emissivity = 0.4 (-0.3181 – 0.0000) + 0.8 (0.8563 – 0.3118) = 0.5578.
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The monochromatic emissivity € of a diffuse surface at 1600 K varies with wavelength in the following manner€ = 0.4 for 0 < λ < 2= 0.8 for 2 < λ < 5Determine the total emissivitya)0.5558b)0.5568c)0.5578d)0.5588Correct answer is option 'C'. Can you explain this answer?
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