Two varieties of oil are mixed in the ratio 4:3 to produce first quali...
To solve this problem, we can use the concept of ratios and proportions. Let's break down the problem into steps:
Step 1: Calculate the ratio of the two varieties of oil in the first and second qualities.
- In the first quality, the ratio of the two varieties of oil is given as 4:3.
- In the second quality, the ratio of the two varieties of oil is given as 2:3.
Step 2: Determine the quantities of the two varieties of oil in the first and second qualities.
- Let's assume the quantities of the two varieties of oil in the first quality are 4x and 3x, respectively.
- Similarly, let's assume the quantities of the two varieties of oil in the second quality are 2y and 3y, respectively.
Step 3: Set up a proportion to find the value of x.
- Since the total quantity of oil in the first quality is not given, we can assume it to be a certain value, let's say k.
- Using the given ratio of 4:3, we can set up the proportion: 4x/k = 3x/k.
- Cross-multiplying, we get 4xk = 3xk.
- Dividing both sides by x, we get 4k = 3k.
- Simplifying, we find k = 0.
Step 4: Calculate the quantity of the first quality oil needed to produce the third quality.
- Let's assume the quantity of the first quality oil needed to produce the third quality is m kg.
- Using the given ratio of 5:4 for the third quality, we can set up the proportion: 4x/m = 5y/10.
- Cross-multiplying, we get 4xm = 5y*10.
- Simplifying, we find 4xm = 50y.
- Dividing both sides by 4x, we get m = 50y/4x.
Step 5: Substitute the values of x and y.
- We know that x = 0 (from Step 3) and y = 10 (given in the problem).
- Substituting these values, we get m = 50*10/4*0.
- Since 0 is in the denominator, we cannot divide by it. This means that there is no specific quantity of the first quality oil needed to produce the third quality.
Hence, the answer is D) 98 kg.
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