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The radiant heat transfer from a plate of 2.5 cm2 area at 1250 K to a very cold enclosure is 5.0 W. Determine the emissivity of the plate at this temperature
  • a)
    0.444
  • b)
    0.344
  • c)
    0.244
  • d)
    0.144
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The radiant heat transfer from a plate of 2.5 cm2area at 1250 K to a v...
Emissivity = E/σ A T4 = 0.144.
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The radiant heat transfer from a plate of 2.5 cm2area at 1250 K to a v...
Given:
Area of the plate (A) = 2.5 cm²
Temperature of the plate (T) = 1250 K
Radiant heat transfer from the plate (q) = 5.0 W

We need to determine the emissivity of the plate at this temperature.

Radiant Heat Transfer:
The radiant heat transfer from a surface can be determined by the Stefan-Boltzmann law, which is given by:

q = εσAT⁴

where,
ε = Emissivity of the surface
σ = Stefan-Boltzmann constant (5.67 x 10^-8 W/m²K⁴)
A = Area of the surface
T = Temperature of the surface

Solving for emissivity (ε):

ε = q / (σAT⁴)

Substituting the given values, we get:

ε = 5.0 / (5.67 x 10^-8 x 2.5 x 10^-4 x (1250)^4)

ε = 0.144

Therefore, the emissivity of the plate at 1250 K is 0.144.

Answer: Option D (0.144)
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