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A furnace emits radiation at 2000 K. Treating it as a black body radiation, calculate the wavelength at which emission is maximum
- a)1.449 * 10 -6 m
- b)2.449 * 10 -6 m
- c)3.449 * 10 -6 m
- d)4.449 * 10 -6 m
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A furnace emits radiation at 2000 K. Treating it as a black body radia...
(Wavelength) T = 2.8908 * 10 -3. So, wavelength = 1.449 * 10 -6 m.
Most Upvoted Answer
A furnace emits radiation at 2000 K. Treating it as a black body radia...
Solution:
The wavelength at which emission is maximum can be calculated using Wien's displacement law which states that the product of the wavelength at which emission is maximum and the temperature of the black body is a constant.
Mathematically,
λmaxT = b
where λmax is the wavelength at which emission is maximum, T is the temperature of the black body, and b is a constant known as Wien's displacement constant.
The value of Wien's displacement constant is given by
b = 2.898 × 10^-3 m K
Given that the temperature of the furnace is 2000 K, we can calculate the wavelength at which emission is maximum as follows.
λmax = b/T
λmax = 2.898 × 10^-3 m K / 2000 K
λmax = 1.449 × 10^-6 m
Therefore, the correct answer is option (a) 1.449 × 10^-6 m.
The wavelength at which emission is maximum can be calculated using Wien's displacement law which states that the product of the wavelength at which emission is maximum and the temperature of the black body is a constant.
Mathematically,
λmaxT = b
where λmax is the wavelength at which emission is maximum, T is the temperature of the black body, and b is a constant known as Wien's displacement constant.
The value of Wien's displacement constant is given by
b = 2.898 × 10^-3 m K
Given that the temperature of the furnace is 2000 K, we can calculate the wavelength at which emission is maximum as follows.
λmax = b/T
λmax = 2.898 × 10^-3 m K / 2000 K
λmax = 1.449 × 10^-6 m
Therefore, the correct answer is option (a) 1.449 × 10^-6 m.
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