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The specific gravity of 98% H2SO4 is 1.8 g/cc.50 ml of this solution is mixed with 1750 ml of pure water.Molarity of resulting solution is?
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Calculation of Molarity of Resulting Solution
Calculating Moles of H2SO4 in Initial Solution
Calculating Moles of H2SO4 in Water
Calculating Total Moles of H2SO4 in Resulting Solution
Final Calculation of Molarity of Resulting Solution
Molarity = total moles of H2SO4 / total volume of resulting solution = 0.918 moles /
To calculate the molarity of the resulting solution, we need to first calculate the number of moles of H2SO4 in the initial solution and then add it to the moles of H2SO4 in the water to get the total moles of H2SO4 in the resulting solution. The formula for calculating molarity is:
Molarity = moles of solute / volume of solution in liters
Calculating Moles of H2SO4 in Initial Solution
The specific gravity of 98% H2SO4 is 1.8 g/cc, which means that the density of the solution is 1.8 g per 1 cc (or 1 ml). Therefore, the mass of 50 ml of 98% H2SO4 solution can be calculated as:
Mass of H2SO4 = volume x density = 50 x 1.8 = 90 g
The molar mass of H2SO4 is 98 g/mol, so the number of moles of H2SO4 in 90 g of the solution can be calculated as:
Moles of H2SO4 = mass of H2SO4 / molar mass of H2SO4 = 90 / 98 = 0.918 moles
Calculating Moles of H2SO4 in Water
The volume of water added to the initial solution is 1750 ml, or 1.75 liters. Since the water is pure, it does not contain any H2SO4, so the number of moles of H2SO4 in the water is zero.
Calculating Total Moles of H2SO4 in Resulting Solution
The total number of moles of H2SO4 in the resulting solution is the sum of the moles of H2SO4 in the initial solution and the moles of H2SO4 in the water. Therefore:
Total moles of H2SO4 = moles of H2SO4 in initial solution + moles of H2SO4 in water = 0.918 moles + 0 moles = 0.918 moles
The total volume of the resulting solution is the sum of the volumes of the initial solution and the water. Therefore:
Total volume of resulting solution = volume of initial solution + volume of water = 50 ml + 1750 ml = 1800 ml = 1.8 liters
Final Calculation of Molarity of Resulting Solution
Now that we know the total number of moles of H2SO4 in the resulting solution and the total volume of the resulting solution, we can calculate the molarity of the resulting solution using the formula:
Molarity = moles of solute / volume of solution in liters
Therefore, the molarity of the resulting solution is:
Molarity = total moles of H2SO4 / total volume of resulting solution = 0.918 moles /
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The specific gravity of 98% H2SO4 is 1.8 g/cc.50 ml of this solution is mixed with 1750 ml of pure water.Molarity of resulting solution is?
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The specific gravity of 98% H2SO4 is 1.8 g/cc.50 ml of this solution is mixed with 1750 ml of pure water.Molarity of resulting solution is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The specific gravity of 98% H2SO4 is 1.8 g/cc.50 ml of this solution is mixed with 1750 ml of pure water.Molarity of resulting solution is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The specific gravity of 98% H2SO4 is 1.8 g/cc.50 ml of this solution is mixed with 1750 ml of pure water.Molarity of resulting solution is?.
The specific gravity of 98% H2SO4 is 1.8 g/cc.50 ml of this solution is mixed with 1750 ml of pure water.Molarity of resulting solution is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The specific gravity of 98% H2SO4 is 1.8 g/cc.50 ml of this solution is mixed with 1750 ml of pure water.Molarity of resulting solution is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The specific gravity of 98% H2SO4 is 1.8 g/cc.50 ml of this solution is mixed with 1750 ml of pure water.Molarity of resulting solution is?.
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