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A metal sphere of surface area 0.0225 m2 is in an evacuated enclosure whose walls are held at a very low temperature. Electric current is passed through resistors imbedded in the sphere causing electrical energy to be dissipated at the rate of 75 W. If the sphere surfaces temperature is measured to be 560 K, while in steady state, calculate emissivity of the sphere surface
- a)0.498
- b)0.598
- c)0.698
- d)0.798
Correct answer is option 'B'. Can you explain this answer?
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A metal sphere of surface area 0.0225 m2is in an evacuated enclosure w...
E = e A σ b T.
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A metal sphere of surface area 0.0225 m2is in an evacuated enclosure w...
To determine the emissivity of the metal sphere's surface, we can use the Stefan-Boltzmann law, which relates the power radiated by an object to its temperature and emissivity. The equation is given by:
P = εσA(T^4)
Where:
P = power radiated (W)
ε = emissivity
σ = Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4)
A = surface area of the sphere (m^2)
T = temperature of the sphere (K)
We are given the power dissipated, the surface area, and the temperature. We can rearrange the equation to solve for emissivity:
ε = P / (σA(T^4))
Now, let's substitute the given values:
P = 75 W
A = 0.0225 m^2
T = 560 K
σ = 5.67 x 10^-8 W/m^2K^4
Plugging in these values, we get:
ε = 75 / (5.67 x 10^-8 x 0.0225 x (560^4))
Calculating this expression, we find ε ≈ 0.5977.
Therefore, the emissivity of the metal sphere's surface is approximately 0.598.
So, option 'B' is the correct answer.
P = εσA(T^4)
Where:
P = power radiated (W)
ε = emissivity
σ = Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4)
A = surface area of the sphere (m^2)
T = temperature of the sphere (K)
We are given the power dissipated, the surface area, and the temperature. We can rearrange the equation to solve for emissivity:
ε = P / (σA(T^4))
Now, let's substitute the given values:
P = 75 W
A = 0.0225 m^2
T = 560 K
σ = 5.67 x 10^-8 W/m^2K^4
Plugging in these values, we get:
ε = 75 / (5.67 x 10^-8 x 0.0225 x (560^4))
Calculating this expression, we find ε ≈ 0.5977.
Therefore, the emissivity of the metal sphere's surface is approximately 0.598.
So, option 'B' is the correct answer.
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A metal sphere of surface area 0.0225 m2is in an evacuated enclosure whose walls are held at a very low temperature. Electric current is passed through resistors imbedded in the sphere causing electrical energy to be dissipated at the rate of 75 W. If the sphere surfaces temperature is measured to be 560 K, while in steady state, calculate emissivity of the sphere surfacea)0.498b)0.598c)0.698d)0.798Correct answer is option 'B'. Can you explain this answer?
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A metal sphere of surface area 0.0225 m2is in an evacuated enclosure whose walls are held at a very low temperature. Electric current is passed through resistors imbedded in the sphere causing electrical energy to be dissipated at the rate of 75 W. If the sphere surfaces temperature is measured to be 560 K, while in steady state, calculate emissivity of the sphere surfacea)0.498b)0.598c)0.698d)0.798Correct answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A metal sphere of surface area 0.0225 m2is in an evacuated enclosure whose walls are held at a very low temperature. Electric current is passed through resistors imbedded in the sphere causing electrical energy to be dissipated at the rate of 75 W. If the sphere surfaces temperature is measured to be 560 K, while in steady state, calculate emissivity of the sphere surfacea)0.498b)0.598c)0.698d)0.798Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal sphere of surface area 0.0225 m2is in an evacuated enclosure whose walls are held at a very low temperature. Electric current is passed through resistors imbedded in the sphere causing electrical energy to be dissipated at the rate of 75 W. If the sphere surfaces temperature is measured to be 560 K, while in steady state, calculate emissivity of the sphere surfacea)0.498b)0.598c)0.698d)0.798Correct answer is option 'B'. Can you explain this answer?.
A metal sphere of surface area 0.0225 m2is in an evacuated enclosure whose walls are held at a very low temperature. Electric current is passed through resistors imbedded in the sphere causing electrical energy to be dissipated at the rate of 75 W. If the sphere surfaces temperature is measured to be 560 K, while in steady state, calculate emissivity of the sphere surfacea)0.498b)0.598c)0.698d)0.798Correct answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A metal sphere of surface area 0.0225 m2is in an evacuated enclosure whose walls are held at a very low temperature. Electric current is passed through resistors imbedded in the sphere causing electrical energy to be dissipated at the rate of 75 W. If the sphere surfaces temperature is measured to be 560 K, while in steady state, calculate emissivity of the sphere surfacea)0.498b)0.598c)0.698d)0.798Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal sphere of surface area 0.0225 m2is in an evacuated enclosure whose walls are held at a very low temperature. Electric current is passed through resistors imbedded in the sphere causing electrical energy to be dissipated at the rate of 75 W. If the sphere surfaces temperature is measured to be 560 K, while in steady state, calculate emissivity of the sphere surfacea)0.498b)0.598c)0.698d)0.798Correct answer is option 'B'. Can you explain this answer?.
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