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2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]
- a)0.955 M and 1.910 M
- b)1.910 M and 0.955 M
- c)1.90 M and 1.910 M
- d)0.477 M and 0.477 M
Correct answer is option 'B'. Can you explain this answer?
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To find the molar concentration of sodium ions and carbonate ions, we first need to calculate the number of moles of sodium carbonate dissolved in the solution.
We are given that 2.53 g of sodium carbonate is dissolved in enough water to make 250 mL of solution. To find the number of moles, we need to convert grams to moles using the molar mass of sodium carbonate.
The molar mass of sodium carbonate (Na2CO3) is:
(2 x atomic mass of sodium) + atomic mass of carbon + (3 x atomic mass of oxygen)
= (2 x 22.99 g/mol) + 12.01 g/mol + (3 x 16.00 g/mol)
= 46.00 g/mol + 12.01 g/mol + 48.00 g/mol
= 106.01 g/mol
Now, we can calculate the number of moles of sodium carbonate:
moles = mass / molar mass
moles = 2.53 g / 106.01 g/mol
moles ≈ 0.0239 mol
Since sodium carbonate dissociates completely, each mole of sodium carbonate produces 2 moles of sodium ions (Na+) and 1 mole of carbonate ions (CO32-). Therefore, the molar concentration of sodium ions and carbonate ions in the solution will be equal to the number of moles of sodium carbonate.
The molar concentration of sodium ions (Na+) and carbonate ions (CO32-) is approximately 0.0239 mol/L.
We are given that 2.53 g of sodium carbonate is dissolved in enough water to make 250 mL of solution. To find the number of moles, we need to convert grams to moles using the molar mass of sodium carbonate.
The molar mass of sodium carbonate (Na2CO3) is:
(2 x atomic mass of sodium) + atomic mass of carbon + (3 x atomic mass of oxygen)
= (2 x 22.99 g/mol) + 12.01 g/mol + (3 x 16.00 g/mol)
= 46.00 g/mol + 12.01 g/mol + 48.00 g/mol
= 106.01 g/mol
Now, we can calculate the number of moles of sodium carbonate:
moles = mass / molar mass
moles = 2.53 g / 106.01 g/mol
moles ≈ 0.0239 mol
Since sodium carbonate dissociates completely, each mole of sodium carbonate produces 2 moles of sodium ions (Na+) and 1 mole of carbonate ions (CO32-). Therefore, the molar concentration of sodium ions and carbonate ions in the solution will be equal to the number of moles of sodium carbonate.
The molar concentration of sodium ions (Na+) and carbonate ions (CO32-) is approximately 0.0239 mol/L.
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2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910 Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer?
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2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910 Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about 2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910 Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910 Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer?.
2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910 Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about 2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910 Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910 Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer?.
Solutions for 2 5. 3 g of sodium carbonate, Na2 CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, CO32– are respectively (Molar mass of Na2CO3 = 106 g mol–1) [2010]a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910 Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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