Electromagnetic waves strikes a hot body maintained at 900 degree Cels...
Absorptivity + Reflectivity + Transmissivity = 1. So, incident flux = 60/0.318 = 188.67 W/m2.
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Electromagnetic waves strikes a hot body maintained at 900 degree Cels...
Understanding the Problem
When electromagnetic waves strike a hot body, the energy can be reflected, transmitted, or absorbed. The sum of these three properties must equal 1:
- Reflectivity (ρ) = 0.66
- Transmissivity (τ) = 0.022
- Absorptivity (α) = 1 - (ρ + τ)
Given that the absorbed flux (α * I) is 60 W/m2, we need to determine the rate of incident flux (I).
Calculating Absorptivity
To find absorptivity (α):
- α = 1 - (ρ + τ)
- α = 1 - (0.66 + 0.022) = 1 - 0.682 = 0.318
Using the Relationship Between Absorbed Flux and Incident Flux
The relationship between the absorbed flux, incident flux, and absorptivity is given by:
- Absorbed flux = α * I
Substituting the values:
- 60 W/m2 = 0.318 * I
To find the incident flux (I):
- I = 60 W/m2 / 0.318 = 188.67 W/m2
Conclusion
The rate of incident flux is 188.67 W/m2, which corresponds to option 'C'.
This calculation demonstrates the importance of understanding the interactions of electromagnetic waves with materials and how to apply fundamental principles to derive key quantities in thermal radiation.