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The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer?.

Solutions for The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]a)44.8 km/sb)22.4 km/sc)11.2 km/s (remains unchanged)d)5.6 km/sCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.