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When ultraviolet radiation is incident on asurface, no photoelectrons are emitted. If asecond beam causes photoelectrons to beejected, it may consists of    [2002]
  • a)
    infra-red waves
  • b)
    X-rays
  • c)
    visible light rays
  • d)
    radio waves
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
When ultraviolet radiation is incident on asurface, no photoelectrons ...
Energy of photon of X-rays is more than
energy of photon of ultraviolet rays. Because
frequency of X rays is more than ultraviolet
rays.
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Most Upvoted Answer
When ultraviolet radiation is incident on asurface, no photoelectrons ...
Explanation:

When ultraviolet (UV) radiation is incident on a surface, it has enough energy to cause the ejection of electrons from the surface. This phenomenon is known as the photoelectric effect. However, it is possible for a surface to not emit any photoelectrons when UV radiation is incident on it.

Photoelectric Effect:
The photoelectric effect occurs when photons (particles of light) with sufficient energy are incident on a material surface, causing the ejection of electrons. The energy of a photon is directly proportional to its frequency, according to the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the photon.

Explanation of Options:
a) Infrared waves: Infrared waves have lower frequencies and energies compared to ultraviolet radiation. Therefore, they do not have enough energy to cause the photoelectric effect. So, they cannot cause the emission of photoelectrons. Hence, option (a) is incorrect.

b) X-rays: X-rays have higher frequencies and energies compared to ultraviolet radiation. They have enough energy to cause the photoelectric effect and eject photoelectrons. Therefore, X-rays can cause the emission of photoelectrons. Hence, option (b) is correct.

c) Visible light rays: Visible light rays have energies that fall between infrared and ultraviolet radiation. Some frequencies of visible light can cause the photoelectric effect and emit photoelectrons, while others may not. Therefore, it is possible for visible light to cause the emission of photoelectrons, but it is not always guaranteed. Hence, option (c) is incorrect.

d) Radio waves: Radio waves have much lower frequencies and energies compared to ultraviolet radiation. They do not have enough energy to cause the photoelectric effect and eject photoelectrons. Therefore, radio waves cannot cause the emission of photoelectrons. Hence, option (d) is incorrect.

Conclusion:
Out of the given options, only X-rays have enough energy to cause the photoelectric effect and eject photoelectrons. Therefore, the correct answer is option (b) - X-rays.
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Community Answer
When ultraviolet radiation is incident on asurface, no photoelectrons ...
Bcz now we have req.more energy it means less wavelength only option B is possible
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When ultraviolet radiation is incident on asurface, no photoelectrons are emitted. If asecond beam causes photoelectrons to beejected, it may consists of [2002]a)infra-red wavesb)X-raysc)visible light raysd)radio wavesCorrect answer is option 'B'. Can you explain this answer?
Question Description
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