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A 3-phase full converter has an average output voltage of 365 V for zero degree firing and resistive load. For a firing angle of 90 degree, the output voltage would be
- a)125 V
- b)569 V
- c)365 V
- d)zero
Correct answer is option 'D'. Can you explain this answer?
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A 3-phase full converter has an average output voltage of 365 V for ze...
Cos 90 = 0.
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A 3-phase full converter has an average output voltage of 365 V for ze...
Full Converter and Firing Angle
Full converter is a type of AC to DC converter that converts the entire AC input voltage into DC output voltage. It uses thyristor as a switching element to control the voltage output. The firing angle is the delay period between the triggering of the thyristor and the point at which the thyristor conducts the current.
Average Output Voltage of Full Converter
The average output voltage of a full converter with a resistive load can be calculated as follows:
Vdc = (2/π)*Vm*cos(α/2)
where Vdc is the DC output voltage, Vm is the peak value of the AC input voltage, and α is the firing angle.
For zero degree firing, α=0, and the output voltage is:
Vdc = (2/π)*Vm*cos(α/2) = (2/π)*Vm*cos(0/2) = (2/π)*Vm = 0.637*Vm
So, if the average output voltage is 365 V for zero degree firing, then the peak value of the AC input voltage is:
Vm = 365/0.637 = 573.7 V
Output Voltage for 90 Degree Firing
For a firing angle of 90 degree, α=90, and the output voltage is:
Vdc = (2/π)*Vm*cos(α/2) = (2/π)*Vm*cos(90/2) = 0
So, the output voltage for 90 degree firing is zero.
Conclusion
The average output voltage of a full converter with a resistive load can be calculated using the formula Vdc = (2/π)*Vm*cos(α/2). For zero degree firing, the output voltage is 0.637*Vm. For a firing angle of 90 degree, the output voltage is zero.
Full converter is a type of AC to DC converter that converts the entire AC input voltage into DC output voltage. It uses thyristor as a switching element to control the voltage output. The firing angle is the delay period between the triggering of the thyristor and the point at which the thyristor conducts the current.
Average Output Voltage of Full Converter
The average output voltage of a full converter with a resistive load can be calculated as follows:
Vdc = (2/π)*Vm*cos(α/2)
where Vdc is the DC output voltage, Vm is the peak value of the AC input voltage, and α is the firing angle.
For zero degree firing, α=0, and the output voltage is:
Vdc = (2/π)*Vm*cos(α/2) = (2/π)*Vm*cos(0/2) = (2/π)*Vm = 0.637*Vm
So, if the average output voltage is 365 V for zero degree firing, then the peak value of the AC input voltage is:
Vm = 365/0.637 = 573.7 V
Output Voltage for 90 Degree Firing
For a firing angle of 90 degree, α=90, and the output voltage is:
Vdc = (2/π)*Vm*cos(α/2) = (2/π)*Vm*cos(90/2) = 0
So, the output voltage for 90 degree firing is zero.
Conclusion
The average output voltage of a full converter with a resistive load can be calculated using the formula Vdc = (2/π)*Vm*cos(α/2). For zero degree firing, the output voltage is 0.637*Vm. For a firing angle of 90 degree, the output voltage is zero.
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A 3-phase full converter has an average output voltage of 365 V for zero degree firing and resistive load. For a firing angle of 90 degree, the output voltage would bea)125 Vb)569 Vc)365 Vd)zeroCorrect answer is option 'D'. Can you explain this answer?
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