A single-phase AC supply is connected to a full wave rectifier through...
Concept:
In a full wave rectifier though a transformer,
Average output voltage, V0 = 2Vm/π
Average output current, I0 = V0/R
RMS value of output voltage Vor = Vs
RMS value of load current, Ior = Vs/R
Average value of diode current, Id = Im/2
RMS value of diode current, Idr = Ior
Peak value of diode current, Idm = √2 Ior
Power delivered to the load = Vor Ior
Input voltamperes = Vs Ior
Calculation:
Given that, DC output voltage (VDC) = 400 V
Average output voltage of rectifier (V0) = 400 V
⇒ Vs = 444.28 V
Load resistance (R) = 10 Ω
RMS value of load current, Ior = 444.2810 = 44.428A
kVA rating of transformer = 444.28 × 44.428 = 19.738 kVA