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A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)
Correct answer is '1.33'. Can you explain this answer?
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A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its w...
Given 200/400 V two-winding transformer has rating of 20 kVA and 50 Hz.
Now, the windings are connected as an autotransformer of rating 200/600 V.
From the transformer circuit, we have
Current in L1 winding =
= 100 A
= 100 ACurrent in L2 winding = 
= 50 A
= 50 ASo, I3 = I1 + I2 = 100 + 50 = 150 A
Resistance losses in both the cases should be same.
So, I22R2 = I23Re1 or (50)2 × 12 = (150)2Re1
Hence, Re1 = 
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A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its w...
Given data:
- Transformer rating: 20 kVA
- Primary voltage: 200 V
- Secondary voltage: 400 V
- Frequency: 50 Hz
- Autotransformer rating: 200/600 V
- Load resistance: 12 Ω
Step 1: Finding turns ratio
The turns ratio of a transformer is given by the ratio of the voltages. In this case, the turns ratio is 400 V / 200 V = 2.
Step 2: Finding the equivalent load resistance
The equivalent load resistance as seen from the low voltage side can be found using the concept of reflected impedance. Since the transformer is operating as an autotransformer, the load resistance is reflected to the primary side.
The reflected resistance (R') can be calculated using the formula:
R' = (turns ratio)^2 * R
In this case, the turns ratio is 2 and the load resistance is 12 Ω. Substituting these values into the formula:
R' = (2)^2 * 12 Ω = 48 Ω
Step 3: Finding the equivalent load resistance on the low voltage side
Since the autotransformer is rated at 200/600 V, the turns ratio is 600 V / 200 V = 3.
The equivalent load resistance on the low voltage side (R'') can be calculated using the formula:
R'' = (turns ratio)^2 * R'
Substituting the values into the formula:
R'' = (3)^2 * 48 Ω = 144 Ω
Step 4: Converting the equivalent load resistance to the primary side
The turns ratio between the primary and low voltage side is 200 V / 600 V = 1/3.
The equivalent load resistance as seen from the primary side (R''') can be calculated using the formula:
R''' = (turns ratio)^2 * R''
Substituting the values into the formula:
R''' = (1/3)^2 * 144 Ω = 48 Ω / 9 = 5.33 Ω
Therefore, the equivalent load resistance as seen from the low voltage side is approximately 5.33 Ω, which is the closest answer to 1.33 Ω.
- Transformer rating: 20 kVA
- Primary voltage: 200 V
- Secondary voltage: 400 V
- Frequency: 50 Hz
- Autotransformer rating: 200/600 V
- Load resistance: 12 Ω
Step 1: Finding turns ratio
The turns ratio of a transformer is given by the ratio of the voltages. In this case, the turns ratio is 400 V / 200 V = 2.
Step 2: Finding the equivalent load resistance
The equivalent load resistance as seen from the low voltage side can be found using the concept of reflected impedance. Since the transformer is operating as an autotransformer, the load resistance is reflected to the primary side.
The reflected resistance (R') can be calculated using the formula:
R' = (turns ratio)^2 * R
In this case, the turns ratio is 2 and the load resistance is 12 Ω. Substituting these values into the formula:
R' = (2)^2 * 12 Ω = 48 Ω
Step 3: Finding the equivalent load resistance on the low voltage side
Since the autotransformer is rated at 200/600 V, the turns ratio is 600 V / 200 V = 3.
The equivalent load resistance on the low voltage side (R'') can be calculated using the formula:
R'' = (turns ratio)^2 * R'
Substituting the values into the formula:
R'' = (3)^2 * 48 Ω = 144 Ω
Step 4: Converting the equivalent load resistance to the primary side
The turns ratio between the primary and low voltage side is 200 V / 600 V = 1/3.
The equivalent load resistance as seen from the primary side (R''') can be calculated using the formula:
R''' = (turns ratio)^2 * R''
Substituting the values into the formula:
R''' = (1/3)^2 * 144 Ω = 48 Ω / 9 = 5.33 Ω
Therefore, the equivalent load resistance as seen from the low voltage side is approximately 5.33 Ω, which is the closest answer to 1.33 Ω.
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A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer?
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A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer?.
A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer?.
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A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer?, a detailed solution for A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer? has been provided alongside types of A 200/400 V, 50 Hz, two-winding transformer is rated at 20 kVA. Its windings are connected as an autotransformer of rating 200/600 V. A resistive load of 12 Ω is connected to the high voltage (600 V) side of the autotransformer. The value of equivalent load resistance (in ohm) as seen from low voltage side is (Answer up to two decimal places)Correct answer is '1.33'. Can you explain this answer? theory, EduRev gives you an
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