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A three-phase full converter charges a battery from a three-phase supply of 230 V. The battery emf is 200 V and the internal resistance of the battery is 0.5 Ω. Find the value of the continuous current which is flowing through the battery if its terminal voltage is 210 V
  • a)
    10 A
  • b)
    20 A
  • c)
    0.5 A
  • d)
    25 A
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A three-phase full converter charges a battery from a three-phase supp...
Vo = 210 V
Vo = E + Io x R
210 = 200 + 0.5 x Io
Io (Current through the battery) = 20 A.
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Most Upvoted Answer
A three-phase full converter charges a battery from a three-phase supp...
To find the value of the continuous current flowing through the battery, we need to analyze the circuit and calculate the current based on the given information.

Given:
Three-phase supply voltage (Vph) = 230 V
Battery emf (Eb) = 200 V
Internal resistance of the battery (R) = 0.5 Ω
Terminal voltage of the battery (Vt) = 210 V

First, let's calculate the effective value of the supply line voltage (Vline) using the given phase voltage (Vph):
Vline = √3 × Vph
= √3 × 230
= 397.9 V

Next, we can find the voltage drop across the internal resistance of the battery (VR) using the formula:
VR = Vt - Eb
= 210 - 200
= 10 V

Now, we can calculate the current flowing through the battery (I) using Ohm's Law:
I = VR / R
= 10 / 0.5
= 20 A

Therefore, the value of the continuous current flowing through the battery is 20 A.
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