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A lead acid battery fitted in an automobile has an emf of 24 volt and has an internal resistance of 0.05 ohm it supplies a total load of 100 w then terminal voltage is?
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A lead acid battery fitted in an automobile has an emf of 24 volt and ...
Terminal Voltage Calculation of Lead Acid Battery in an Automobile

Given:
- EMF (E) = 24 V
- Internal Resistance (r) = 0.05 ohm
- Load (P) = 100 W

Formula:
- Terminal Voltage (V) = E - Ir
- Power (P) = V * I

Solution:
- Power (P) = V * I
- I = P / V
- Terminal Voltage (V) = E - Ir
- Terminal Voltage (V) = 24 - (0.05 * (100/24))
- Terminal Voltage (V) = 22.08 V

Answer: The terminal voltage of the lead-acid battery in an automobile is 22.08 V. When a load of 100 W is supplied, the terminal voltage of the battery drops from its EMF of 24 V to 22.08 V due to the internal resistance of 0.05 ohm.
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A lead acid battery fitted in an automobile has an emf of 24 volt and has an internal resistance of 0.05 ohm it supplies a total load of 100 w then terminal voltage is?
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