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What is the settling velocity of the particle in the wastewater if its diameter is 2 * 10-3cm. Given G=2.65, viscosity v=8 * 10-3cm2/Sec?
- a)0.01cm/Sec
- b)0.13cm/Sec
- c)0.24cm/Sec
- d)0.36cm/Sec
Correct answer is option 'B'. Can you explain this answer?
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What is the settling velocity of the particle in the wastewater if its...
Explanation: Settling velocity of the particle in wastewater is given by vs=g (G-1) d2/18v
Specific gravity G=1, g=981cm2/Sec, viscosity v=8 * 10-3cm2/Sec
vs = 981 * (2.65-1) * 0.002 * 0.002/(18 * 0.008) = 0.13cm/Sec.
Specific gravity G=1, g=981cm2/Sec, viscosity v=8 * 10-3cm2/Sec
vs = 981 * (2.65-1) * 0.002 * 0.002/(18 * 0.008) = 0.13cm/Sec.
Most Upvoted Answer
What is the settling velocity of the particle in the wastewater if its...
To calculate the settling velocity of a particle in wastewater, we can use Stoke's law. Stoke's law describes the motion of a small spherical particle through a viscous fluid. The formula for settling velocity is given by:
v = (2/9) * (g * (ρp - ρf) * d^2) / η
Where:
- v is the settling velocity of the particle
- g is the acceleration due to gravity (980 cm/s^2)
- ρp is the density of the particle
- ρf is the density of the fluid (wastewater)
- d is the diameter of the particle
- η is the viscosity of the fluid (wastewater)
Let's plug in the given values:
- g = 980 cm/s^2
- ρp = 2.65 (dimensionless, since no units are mentioned)
- ρf = density of wastewater (not given)
- d = 2 * 10^-3 cm
- η = 8 * 10^-3 cm^2/s
We can ignore the densities of the particle and the fluid since they are not given. Therefore, the settling velocity equation becomes:
v = (2/9) * (g * d^2) / η
Now let's substitute the values and calculate the settling velocity:
v = (2/9) * (980 * (2 * 10^-3)^2) / (8 * 10^-3)
= (2/9) * (980 * 4 * 10^-6) / (8 * 10^-3)
= (2/9) * (3.92 * 10^-3) / (8 * 10^-3)
= (2/9) * 0.49
= 0.1089 cm/s
The calculated settling velocity is approximately 0.1089 cm/s.
Therefore, the correct option is B) 0.13 cm/s, which is the closest value to the calculated settling velocity.
v = (2/9) * (g * (ρp - ρf) * d^2) / η
Where:
- v is the settling velocity of the particle
- g is the acceleration due to gravity (980 cm/s^2)
- ρp is the density of the particle
- ρf is the density of the fluid (wastewater)
- d is the diameter of the particle
- η is the viscosity of the fluid (wastewater)
Let's plug in the given values:
- g = 980 cm/s^2
- ρp = 2.65 (dimensionless, since no units are mentioned)
- ρf = density of wastewater (not given)
- d = 2 * 10^-3 cm
- η = 8 * 10^-3 cm^2/s
We can ignore the densities of the particle and the fluid since they are not given. Therefore, the settling velocity equation becomes:
v = (2/9) * (g * d^2) / η
Now let's substitute the values and calculate the settling velocity:
v = (2/9) * (980 * (2 * 10^-3)^2) / (8 * 10^-3)
= (2/9) * (980 * 4 * 10^-6) / (8 * 10^-3)
= (2/9) * (3.92 * 10^-3) / (8 * 10^-3)
= (2/9) * 0.49
= 0.1089 cm/s
The calculated settling velocity is approximately 0.1089 cm/s.
Therefore, the correct option is B) 0.13 cm/s, which is the closest value to the calculated settling velocity.
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What is the settling velocity of the particle in the wastewater if its diameter is 2 * 10-3cm. Given G=2.65, viscosity v=8 * 10-3cm2/Sec?a)0.01cm/Secb)0.13cm/Secc)0.24cm/Secd)0.36cm/SecCorrect answer is option 'B'. Can you explain this answer?
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What is the settling velocity of the particle in the wastewater if its diameter is 2 * 10-3cm. Given G=2.65, viscosity v=8 * 10-3cm2/Sec?a)0.01cm/Secb)0.13cm/Secc)0.24cm/Secd)0.36cm/SecCorrect answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about What is the settling velocity of the particle in the wastewater if its diameter is 2 * 10-3cm. Given G=2.65, viscosity v=8 * 10-3cm2/Sec?a)0.01cm/Secb)0.13cm/Secc)0.24cm/Secd)0.36cm/SecCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the settling velocity of the particle in the wastewater if its diameter is 2 * 10-3cm. Given G=2.65, viscosity v=8 * 10-3cm2/Sec?a)0.01cm/Secb)0.13cm/Secc)0.24cm/Secd)0.36cm/SecCorrect answer is option 'B'. Can you explain this answer?.
What is the settling velocity of the particle in the wastewater if its diameter is 2 * 10-3cm. Given G=2.65, viscosity v=8 * 10-3cm2/Sec?a)0.01cm/Secb)0.13cm/Secc)0.24cm/Secd)0.36cm/SecCorrect answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about What is the settling velocity of the particle in the wastewater if its diameter is 2 * 10-3cm. Given G=2.65, viscosity v=8 * 10-3cm2/Sec?a)0.01cm/Secb)0.13cm/Secc)0.24cm/Secd)0.36cm/SecCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the settling velocity of the particle in the wastewater if its diameter is 2 * 10-3cm. Given G=2.65, viscosity v=8 * 10-3cm2/Sec?a)0.01cm/Secb)0.13cm/Secc)0.24cm/Secd)0.36cm/SecCorrect answer is option 'B'. Can you explain this answer?.
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