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To divide a line segment AB internally in the 5 : 2, first a ray AX is drawn so that ∠BAX is an acute angle and then points A1,A2,A3.... are located at equal distance on ray AX and point B is joined to
  • a)
    A6
  • b)
    A2
  • c)
    A3
  • d)
    A7
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
To divide a line segment AB internally in the 5 : 2, first a ray AX is...
To divide a line segment AB in the ratio m : n (when m > n), a ray AX is drawn in such that ∠BAX is an acute angle and then points A1,A2,A3...Am,…..An…. are located at equal distances on the ray AX and then the point B is joined to AnB.
Therefore, according to the question, point B is joined toA7 .
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Most Upvoted Answer
To divide a line segment AB internally in the 5 : 2, first a ray AX is...
To divide a line segment AB in the ratio m : n (when m > n), a ray AX is drawn in such that ∠BAX is an acute angle and then points A1,A2,A3...Am,…..An…. are located at equal distances on the ray AX and then the point B is joined to AnB.
Therefore, according to the question, point B is joined toA7 .
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To divide a line segment AB internally in the 5 : 2, first a ray AX is drawn so that∠BAXis an acute angle and then points A1,A2,A3....are located at equal distance on ray AX and point B is joined toa)A6b)A2c)A3d)A7Correct answer is option 'D'. Can you explain this answer?
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