Question Description
Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer?.

Solutions for Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant s = 5.7 × 10–8 Wm–2K–4 and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close toa)330Kb)660Kc)990Kd)1550KCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.