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From a point P on the level ground, the angle of elevation of the top of a tower is 30°. If the tower is 100m high, the distance between P and the foot of the tower is
  • a)
    100√3m
  • b)
    200√3m
  • c)
    300√3m
  • d)
    150√3m
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
From a point P on the level ground, the angle of elevation of the top ...
Let QR be the height of the tower, then QR = 100 mQ And angle of elevation of the top of the tower be ∠PPR = 30° 
Therefore, the distance between P and the foot of the tower is 100√3 metres.
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Most Upvoted Answer
From a point P on the level ground, the angle of elevation of the top ...
Let AB= height of Tower=100m,
let the angle of elevation be angle ABP=30 degree,
in right triangle ABP-
tan 30= AB/BP,
1/√3=100/BP,
BP=100√3m
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Community Answer
From a point P on the level ground, the angle of elevation of the top ...
From a point P on the level ground, the angle of elevation of the top of a tower is 30 degrees.
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