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With three resistance connected in parallel ,if each dissipates 20 w the total power supplied by the voltage source equals?
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Calculating total power supplied by the voltage source with three resistances connected in parallel

Step 1: Understanding Parallel Circuit


A parallel circuit is a type of electrical circuit where the current flows through multiple paths. In a parallel circuit, each component (resistance) has its own path for current to flow. Hence, the voltage across each component is the same, but the current flowing through each component may be different.

Step 2: Understanding Power Dissipation


Power dissipation is the amount of power that is lost in the form of heat when a current flows through a resistor. It is calculated using the formula P = I^2*R, where P is the power dissipation, I is the current flowing through the resistor, and R is the resistance of the resistor.

Step 3: Calculating Total Resistance


In a parallel circuit, the total resistance is calculated using the formula 1/Rtotal = 1/R1 + 1/R2 + 1/R3, where R1, R2, and R3 are the resistances of the three components connected in parallel.

Assuming each resistance dissipates 20 W, we can calculate the resistance of each component using the formula P = I^2*R. Therefore, R = P/I^2 = 20/1^2 = 20 ohms.

Using the formula for total resistance, we get:

1/Rtotal = 1/20 + 1/20 + 1/20 = 3/20

Rtotal = 20/3 ohms

Step 4: Calculating Total Power Supplied


The total power supplied by the voltage source is calculated using the formula P = V^2/R, where P is the power, V is the voltage across the circuit, and R is the total resistance of the circuit.

Assuming a voltage of 120 V, we can calculate the total power supplied as follows:

P = V^2/Rtotal = 120^2/(20/3) = 540 W

Therefore, the total power supplied by the voltage source is 540 W when three resistances are connected in parallel, and each dissipates 20 W.
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