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Entropy of a saturated liquid at 227°C is 2.6 kJ/kgK. Its latent heat of vaporization is 1800 kJ/kg; then the entropy of saturated vapour at 227°C would be:
  • a)
    2.88 kJ/kg K
  • b)
    6.2 kJ/kg K
  • c)
    7.93 kJ/kg K
  • d)
    10.53 kJ/kg K
Correct answer is option 'B'. Can you explain this answer?
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Entropy Calculation for Saturated Liquid at 227°C

Given data:
Temperature of the saturated liquid (T) = 227°C
Specific entropy of the saturated liquid (s) = 2.6 kJ/kgK

To calculate the entropy of the saturated vapor at 227°C, we need to consider the change in entropy during the phase change from liquid to vapor.

Entropy Calculation for Latent Heat of Vaporization

Given data:
Latent heat of vaporization (h) = 1800 kJ/kg

The latent heat of vaporization represents the amount of energy required to convert 1 kg of liquid into vapor at constant temperature and pressure. This energy is associated with the change in entropy.

Entropy Change during Vaporization
The entropy change during vaporization can be calculated using the formula:

ΔS = ΔH / T

Where:
ΔS = Change in entropy
ΔH = Change in enthalpy (latent heat of vaporization)
T = Temperature

Substituting the given values:
ΔS = 1800 kJ/kg / 227°C = 1800 kJ/kg / (227 + 273) K = 1800 kJ/kg / 500 K = 3.6 kJ/kgK

Entropy Calculation for Saturated Vapor at 227°C

The entropy of the saturated vapor at 227°C can be obtained by adding the entropy of the saturated liquid (2.6 kJ/kgK) with the entropy change during vaporization (3.6 kJ/kgK).

Entropy of saturated vapor = Entropy of saturated liquid + Entropy change during vaporization
Entropy of saturated vapor = 2.6 kJ/kgK + 3.6 kJ/kgK = 6.2 kJ/kgK

Therefore, the entropy of the saturated vapor at 227°C is 6.2 kJ/kgK, which corresponds to option 'B'.
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Entropy of a saturated liquid at 227°C is 2.6 kJ/kgK. Its latent heat of vaporization is 1800 kJ/kg; then the entropy of saturated vapour at 227°C would be:a)2.88 kJ/kg Kb)6.2 kJ/kg Kc)7.93 kJ/kg Kd)10.53 kJ/kg KCorrect answer is option 'B'. Can you explain this answer?
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Entropy of a saturated liquid at 227°C is 2.6 kJ/kgK. Its latent heat of vaporization is 1800 kJ/kg; then the entropy of saturated vapour at 227°C would be:a)2.88 kJ/kg Kb)6.2 kJ/kg Kc)7.93 kJ/kg Kd)10.53 kJ/kg KCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Entropy of a saturated liquid at 227°C is 2.6 kJ/kgK. Its latent heat of vaporization is 1800 kJ/kg; then the entropy of saturated vapour at 227°C would be:a)2.88 kJ/kg Kb)6.2 kJ/kg Kc)7.93 kJ/kg Kd)10.53 kJ/kg KCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Entropy of a saturated liquid at 227°C is 2.6 kJ/kgK. Its latent heat of vaporization is 1800 kJ/kg; then the entropy of saturated vapour at 227°C would be:a)2.88 kJ/kg Kb)6.2 kJ/kg Kc)7.93 kJ/kg Kd)10.53 kJ/kg KCorrect answer is option 'B'. Can you explain this answer?.
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