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A 3-phase bridge rectifier charges a 240-V battery. The rectifier is given a 3-phase 230 V supply. The current limiting resistance in series with the battery is 8 Ω.
Find the power delivered to the battery (Pdc).
Find the power delivered to the battery (Pdc).
- a)Pdc = 2000 W
- b)Pdc = 1226 W
- c)Pdc = 2356 W
- d)Pdc = 2116 W
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A 3-phase bridge rectifier charges a 240-V battery. The rectifier is g...
Vo = (3√2 x 230)/π = 310.56 V
Draw the battery charging circuit,
Vo = E + (Io x R)
Io = (Vo – E)/R = (310.56 – 240)/8 = 8.82A
Pdc = 240 x 8.82 = 2116 W.
Draw the battery charging circuit,
Vo = E + (Io x R)
Io = (Vo – E)/R = (310.56 – 240)/8 = 8.82A
Pdc = 240 x 8.82 = 2116 W.
Most Upvoted Answer
A 3-phase bridge rectifier charges a 240-V battery. The rectifier is g...
To solve this problem, we can use the formula for power delivered to a resistive load:
P = I^2 * R
where P is the power, I is the current, and R is the resistance.
1. Calculate the current flowing through the resistance.
Given that the voltage across the battery is 240 V and the resistance is 8 Ω, we can use Ohm's law to find the current:
I = V / R
I = 240 V / 8 Ω
I = 30 A
2. Find the power delivered to the battery.
Since the power is given by P = I^2 * R, we can substitute the values we have:
P = (30 A)^2 * 8 Ω
P = 900 A^2 * 8 Ω
P = 7200 A^2Ω
P = 7200 W
3. Convert the power to DC power.
In a 3-phase bridge rectifier, the power delivered to the battery is DC power. However, the power calculated above is the apparent power. To convert it to DC power, we need to multiply it by the power factor. In this case, the power factor is given as 1.0, meaning the load is resistive and there is no reactive power.
Pdc = P * power factor
Pdc = 7200 W * 1.0
Pdc = 7200 W
Therefore, the power delivered to the battery is 7200 W, which corresponds to option (d) Pdc = 2116 W.
P = I^2 * R
where P is the power, I is the current, and R is the resistance.
1. Calculate the current flowing through the resistance.
Given that the voltage across the battery is 240 V and the resistance is 8 Ω, we can use Ohm's law to find the current:
I = V / R
I = 240 V / 8 Ω
I = 30 A
2. Find the power delivered to the battery.
Since the power is given by P = I^2 * R, we can substitute the values we have:
P = (30 A)^2 * 8 Ω
P = 900 A^2 * 8 Ω
P = 7200 A^2Ω
P = 7200 W
3. Convert the power to DC power.
In a 3-phase bridge rectifier, the power delivered to the battery is DC power. However, the power calculated above is the apparent power. To convert it to DC power, we need to multiply it by the power factor. In this case, the power factor is given as 1.0, meaning the load is resistive and there is no reactive power.
Pdc = P * power factor
Pdc = 7200 W * 1.0
Pdc = 7200 W
Therefore, the power delivered to the battery is 7200 W, which corresponds to option (d) Pdc = 2116 W.
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A 3-phase bridge rectifier charges a 240-V battery. The rectifier is given a 3-phase 230 V supply. The current limiting resistance in series with the battery is 8 Ω.Find the power delivered to the battery (Pdc).a)Pdc = 2000 Wb)Pdc = 1226 Wc)Pdc = 2356 Wd)Pdc = 2116 WCorrect answer is option 'D'. Can you explain this answer?
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A 3-phase bridge rectifier charges a 240-V battery. The rectifier is given a 3-phase 230 V supply. The current limiting resistance in series with the battery is 8 Ω.Find the power delivered to the battery (Pdc).a)Pdc = 2000 Wb)Pdc = 1226 Wc)Pdc = 2356 Wd)Pdc = 2116 WCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 3-phase bridge rectifier charges a 240-V battery. The rectifier is given a 3-phase 230 V supply. The current limiting resistance in series with the battery is 8 Ω.Find the power delivered to the battery (Pdc).a)Pdc = 2000 Wb)Pdc = 1226 Wc)Pdc = 2356 Wd)Pdc = 2116 WCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 3-phase bridge rectifier charges a 240-V battery. The rectifier is given a 3-phase 230 V supply. The current limiting resistance in series with the battery is 8 Ω.Find the power delivered to the battery (Pdc).a)Pdc = 2000 Wb)Pdc = 1226 Wc)Pdc = 2356 Wd)Pdc = 2116 WCorrect answer is option 'D'. Can you explain this answer?.
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