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A circular road is constructed outside a square field. The perimeter of the square field is 200 ft. If the width of the road is 7√2 ft. and cost of construction is Rs. 100 per sq. ft. Find the lowest possible cost to construct 50% of the total road.
  • a)
    Rs.70,400
  • b)
    Rs.1,25,400
  • c)
    Rs.1,40,800
  • d)
    Rs.2,35,400
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A circular road is constructed outside a square field. The perimeter o...
The area of the circular road
= π ro2 - π ri2, where ro is the outer radius and ri is the inner radius. 

25= 2508 sq. ft.
If per sq. ft. cost is Rs. 100, then cost of constructing the road = 2508 × 100 = Rs.2,50,800.
Cost of constructing 50% of the road = 50% of the total cost = 250800/2 =Rs.1,25,400
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Most Upvoted Answer
A circular road is constructed outside a square field. The perimeter o...
Ft, what is the area of the remaining area inside the road?

First, we need to find the length of the sides of the square field. Since the perimeter is 200 ft, each side is 50 ft long (200 ÷ 4 = 50).

Next, we need to find the length of the sides of the square that is formed by the inner edge of the road. To do this, we need to subtract twice the width of the road (since there are two sides of the road that are reducing the length of the square) from the length of the sides of the square field.

50 - 2(7) = 36

So the length of the sides of the smaller square is 36 ft.

Now we can find the area of the remaining space inside the road. Since the road is circular, we need to find the area of the circle and subtract it from the area of the smaller square.

The radius of the circle is half the width of the road, so it is 3.5 ft. Using the formula for the area of a circle (πr^2), we can find the area of the circle:

π(3.5)^2 = 38.5π

To find the area of the remaining space inside the road, we need to subtract the area of the circle from the area of the smaller square:

36^2 - 38.5π ≈ 1160.8 ft^2

Therefore, the area of the remaining space inside the road is approximately 1160.8 square feet.
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A circular road is constructed outside a square field. The perimeter of the square field is 200 ft. If the width of the road is 7√2 ft. and cost of construction is Rs. 100 per sq. ft. Find the lowest possible cost to construct 50% of the total road.a)Rs.70,400b)Rs.1,25,400c)Rs.1,40,800d)Rs.2,35,400Correct answer is option 'B'. Can you explain this answer?
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A circular road is constructed outside a square field. The perimeter of the square field is 200 ft. If the width of the road is 7√2 ft. and cost of construction is Rs. 100 per sq. ft. Find the lowest possible cost to construct 50% of the total road.a)Rs.70,400b)Rs.1,25,400c)Rs.1,40,800d)Rs.2,35,400Correct answer is option 'B'. Can you explain this answer? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A circular road is constructed outside a square field. The perimeter of the square field is 200 ft. If the width of the road is 7√2 ft. and cost of construction is Rs. 100 per sq. ft. Find the lowest possible cost to construct 50% of the total road.a)Rs.70,400b)Rs.1,25,400c)Rs.1,40,800d)Rs.2,35,400Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular road is constructed outside a square field. The perimeter of the square field is 200 ft. If the width of the road is 7√2 ft. and cost of construction is Rs. 100 per sq. ft. Find the lowest possible cost to construct 50% of the total road.a)Rs.70,400b)Rs.1,25,400c)Rs.1,40,800d)Rs.2,35,400Correct answer is option 'B'. Can you explain this answer?.
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