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The daily energy produced in a thermal power station is 600 MWh at a load factor of 0.8. What is the maximum demand of the station?
  • a)
    50 MW
  • b)
    31.25 MW
  • c)
    72 MW
  • d)
    600 MW
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The daily energy produced in a thermal power station is 600 MWh at a l...
We know that,
Here t = 24 hours. 
Peak load or maximum demand, 
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The daily energy produced in a thermal power station is 600 MWh at a l...
Calculation:
1. Load Factor:
- Load factor = Average load / Maximum demand
- Given load factor = 0.8
2. Daily Energy Produced:
- Daily energy produced = 600 MWh
- Load factor = 0.8
- Maximum demand = Daily energy produced / Load factor
- Maximum demand = 600 MWh / 0.8
- Maximum demand = 750 MWh
3. Convert MWh to MW:
- 1 MWh = 1 MW for 1 hour
- To convert MWh to MW, divide by 1 hour
- Maximum demand = 750 MW / 24 hours
- Maximum demand = 31.25 MW
Therefore, the maximum demand of the thermal power station is 31.25 MW. Option 'B' is correct.
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The daily energy produced in a thermal power station is 600 MWh at a load factor of 0.8. What is the maximum demand of the station?a)50 MWb)31.25 MWc)72 MWd)600 MWCorrect answer is option 'B'. Can you explain this answer?
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