How many ions are produced in aqueous solution of [Co ( H2O)6 ]Cl2?

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The number of ions produced in an aqueous solution of [Co(H2O)6]Cl2 can be determined by understanding the structure of the compound and its behavior when dissolved in water.

Structure of [Co(H2O)6]Cl2:
- The compound consists of a central cobalt (Co) ion surrounded by six water (H2O) molecules coordinated to it. This results in an octahedral complex with the cobalt ion at the center.
- The chloride (Cl-) ions are present as counterions to balance the charge of the complex. Each chloride ion is not directly coordinated to the cobalt ion.

Dissociation in Aqueous Solution:
When [Co(H2O)6]Cl2 is dissolved in water, it undergoes dissociation, releasing the constituent ions into the solution.

- [Co(H2O)6]2+ ion: The complex ion [Co(H2O)6]2+ remains intact in the solution. It does not dissociate further as the water molecules are strongly coordinated to the cobalt ion.
- Cl- ions: The chloride ions, on the other hand, are free to move and dissociate from the complex. Each chloride ion becomes a separate ion in the solution.

Counting the Ions:
Based on the dissociation, the total number of ions produced in the solution can be determined as follows:

- [Co(H2O)6]Cl2 → [Co(H2O)6]2+ + 2Cl-
- The complex ion [Co(H2O)6]2+ does not dissociate, so it remains as one ion in the solution.
- Each chloride ion (Cl-) dissociates from the complex, resulting in two chloride ions in the solution.

Therefore, the aqueous solution of [Co(H2O)6]Cl2 produces a total of 3 ions: one [Co(H2O)6]2+ ion and two Cl- ions.

Summary:
In summary, the aqueous solution of [Co(H2O)6]Cl2 produces three ions: one [Co(H2O)6]2+ ion and two Cl- ions. The complex ion [Co(H2O)6]2+ remains intact in the solution, while the chloride ions dissociate from the complex.

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