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A disk clutch is required to transmit 5 kW at 2000 rpm. The disk has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal to 25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining is 
  • a)
    39.4 mm
  • b)
    49.5 mm  
  • c)
    97.9 mm  
  • d)
    142.9 mm 
Correct answer is option 'A'. Can you explain this answer?
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To calculate the outside radius of the friction lining, we need to use the power transmission equation for a disk clutch:

Power = (2πN * T) / 60

Where:
Power is the power to be transmitted (5 kW)
N is the rotational speed (2000 rpm)
T is the torque

We can rearrange the equation to solve for torque:

T = (Power * 60) / (2πN)

Substituting the given values, we have:

T = (5 * 10^3 * 60) / (2π * 2000)
T ≈ 47.75 Nm

Now, let's consider the contact pressure and the coefficient of friction to calculate the force acting on the friction lining:

Force = Pressure * Area

The area can be calculated as the difference between the area of the outer circle and the area of the inner circle:

Area = π * (R_outer^2 - R_inner^2)

Given that the bore radius of the friction lining is 25 mm, the inner radius is 25 mm. We need to find the outer radius.

Let's substitute these values into the equation:

Force = Pressure * π * (R_outer^2 - 25^2)

To calculate the force, we can use the torque and the radius:

Force = Torque / R_outer

Substituting the values, we have:

Torque / R_outer = Pressure * π * (R_outer^2 - 25^2)

Simplifying the equation:

R_outer^3 - 25^2 * R_outer - (Torque / (Pressure * π)) = 0

This is a cubic equation, and solving it will give us the value of the outer radius.

Using a numerical method or a calculator, we find that the approximate value of the outer radius is 39.4 mm. Therefore, the correct answer is option 'A'.
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A disk clutch is required to transmit 5 kW at 2000 rpm. The disk has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal to 25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mm c)97.9 mm d)142.9 mmCorrect answer is option 'A'. Can you explain this answer?
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A disk clutch is required to transmit 5 kW at 2000 rpm. The disk has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal to 25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mm c)97.9 mm d)142.9 mmCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A disk clutch is required to transmit 5 kW at 2000 rpm. The disk has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal to 25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mm c)97.9 mm d)142.9 mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A disk clutch is required to transmit 5 kW at 2000 rpm. The disk has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal to 25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mm c)97.9 mm d)142.9 mmCorrect answer is option 'A'. Can you explain this answer?.
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