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A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining is
- a)39.4 mm
- b)49.5 mm
- c)97.9 mm
- d)142.9 mm
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a...
Power Transmitted = 5 kW
N = 2000 rpm
μ = 0.25
r1 = 25 mm
Uniform Pressure = 1 MPa
T = 23.87 N-m
Pressure
ro= 39.4 mm
Bolts in a rigid flangecoupling fails in shear and crushing.
N = 2000 rpm
μ = 0.25
r1 = 25 mm
Uniform Pressure = 1 MPa
T = 23.87 N-m
Pressure
ro= 39.4 mm
Bolts in a rigid flangecoupling fails in shear and crushing.
Most Upvoted Answer
A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a...
To determine the outside radius of the friction lining in the disc clutch, we can use the formula for power transmitted through a clutch:
Power = (2πNτμR^2)/60
Where:
Power = 5 kW
N = 2000 rpm
τ = uniform contact pressure = 1 MPa (10^6 Pa)
μ = coefficient of friction = 0.25
R = outside radius of the friction lining (unknown)
Let's solve for R:
Step 1: Convert power from kW to W and rpm to rad/s
Power = 5 kW = 5000 W
N = 2000 rpm = (2000/60) rad/s = 33.33 rad/s
Step 2: Substitute the given values into the formula and solve for R
5000 = (2π * 33.33 * 10^6 * 0.25 * R^2)/60
Step 3: Simplify the equation
5000 * 60 = 2π * 33.33 * 10^6 * 0.25 * R^2
300000 = 2π * 33.33 * 10^6 * 0.25 * R^2
Step 4: Rearrange the equation to solve for R
R^2 = (300000) / (2π * 33.33 * 10^6 * 0.25)
R^2 = 0.00226
R = √(0.00226)
R ≈ 0.047 m
R ≈ 47 mm
Therefore, the outside radius of the friction lining is approximately 47 mm.
The correct answer is option 'A' (39.4 mm), which is not the same as the calculated value. It is possible that there was a mistake in the question or answer choices provided.
Power = (2πNτμR^2)/60
Where:
Power = 5 kW
N = 2000 rpm
τ = uniform contact pressure = 1 MPa (10^6 Pa)
μ = coefficient of friction = 0.25
R = outside radius of the friction lining (unknown)
Let's solve for R:
Step 1: Convert power from kW to W and rpm to rad/s
Power = 5 kW = 5000 W
N = 2000 rpm = (2000/60) rad/s = 33.33 rad/s
Step 2: Substitute the given values into the formula and solve for R
5000 = (2π * 33.33 * 10^6 * 0.25 * R^2)/60
Step 3: Simplify the equation
5000 * 60 = 2π * 33.33 * 10^6 * 0.25 * R^2
300000 = 2π * 33.33 * 10^6 * 0.25 * R^2
Step 4: Rearrange the equation to solve for R
R^2 = (300000) / (2π * 33.33 * 10^6 * 0.25)
R^2 = 0.00226
R = √(0.00226)
R ≈ 0.047 m
R ≈ 47 mm
Therefore, the outside radius of the friction lining is approximately 47 mm.
The correct answer is option 'A' (39.4 mm), which is not the same as the calculated value. It is possible that there was a mistake in the question or answer choices provided.
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A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer?
Question Description
A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer?.
A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer?.
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A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A disc clutch is required to transmit 5 kW at 2000 rpm. The disc has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal 0.25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining isa)39.4 mmb)49.5 mmc)97.9 mmd)142.9 mmCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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