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In 200 g of water 0.01 mole of NaCI and 0.02 mole of sucrose are dissolved. Assuming solution to be ideal, the depression in freezing point of water (in oC) will be ________. (final answer should be rounded off to two decimal places) [Given : Kf(H2O) = 1.86 K kg mol–1]
    Correct answer is '0.37'. Can you explain this answer?
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    In 200 g of water 0.01 mole of NaCI and 0.02 mole of sucrose are disso...
    Solution:

    Given:
    Mass of water (w) = 200 g
    Moles of NaCl (n1) = 0.01 mole
    Moles of sucrose (n2) = 0.02 mole
    Kf(H2O) = 1.86 K kg mol-1

    The depression in freezing point of water (ΔTf) is given by the formula:

    ΔTf = Kf × w2 × (n1 + n2)

    where w2 is the molecular weight of solvent in kg mol-1.

    Calculation:
    Molecular weight of water (w2) = 18.015 g mol-1 / 1000 = 0.018015 kg mol-1

    Molecular weight of NaCl = 58.44 g mol-1
    Molecular weight of sucrose = 342.3 g mol-1

    Total moles of solute (n1 + n2) = 0.01 + 0.02 = 0.03 mol

    Substituting the values in the formula, we get:

    ΔTf = 1.86 × 0.2 × 0.03 / 0.018015 = 0.37 K

    Therefore, the depression in freezing point of water is 0.37 oC.

    Hence, the answer is '0.37'.
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    In 200 g of water 0.01 mole of NaCI and 0.02 mole of sucrose are disso...
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    In 200 g of water 0.01 mole of NaCI and 0.02 mole of sucrose are dissolved. Assuming solution to be ideal, the depression in freezing point of water (in oC) will be ________. (final answer should be rounded off to two decimal places) [Given : Kf(H2O) = 1.86 K kg mol–1]Correct answer is '0.37'. Can you explain this answer?
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    In 200 g of water 0.01 mole of NaCI and 0.02 mole of sucrose are dissolved. Assuming solution to be ideal, the depression in freezing point of water (in oC) will be ________. (final answer should be rounded off to two decimal places) [Given : Kf(H2O) = 1.86 K kg mol–1]Correct answer is '0.37'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In 200 g of water 0.01 mole of NaCI and 0.02 mole of sucrose are dissolved. Assuming solution to be ideal, the depression in freezing point of water (in oC) will be ________. (final answer should be rounded off to two decimal places) [Given : Kf(H2O) = 1.86 K kg mol–1]Correct answer is '0.37'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In 200 g of water 0.01 mole of NaCI and 0.02 mole of sucrose are dissolved. Assuming solution to be ideal, the depression in freezing point of water (in oC) will be ________. (final answer should be rounded off to two decimal places) [Given : Kf(H2O) = 1.86 K kg mol–1]Correct answer is '0.37'. Can you explain this answer?.
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