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A stop watch time study on an operator with a performance rating of 120 yielded a time of 2 minute. If allowances of 10% of the total available time are to be given, the standard time of the operation is: 
  • a)
    2 minutes
  • b)
    2.4 minutes    
  • c)
    2.64 minutes  
  • d)
    2.67 minutes 
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A stop watch time study on an operator with a performance rating of 12...
Standard time of the operation = Basic time + Allowances 

Standard time of the operation = 2.4 + 0.24 = 2.64 minutes. 
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Most Upvoted Answer
A stop watch time study on an operator with a performance rating of 12...
Explanation:
To find the standard time of the operation, we need to consider the performance rating and the allowances given.

Given:
Performance rating = 120
Time measured = 2 minutes
Allowances = 10% of the total available time

Step 1: Calculate the total available time
To calculate the total available time, we divide the measured time by the performance rating:

Total available time = Time measured / Performance rating
= 2 minutes / 120
= 0.0167 minutes

Step 2: Calculate the allowances
To calculate the allowances, we multiply the total available time by the percentage allowances:

Allowances = Total available time * Percentage allowances
= 0.0167 minutes * 10%
= 0.00167 minutes

Step 3: Calculate the standard time
To calculate the standard time, we add the total available time and the allowances:

Standard time = Total available time + Allowances
= 0.0167 minutes + 0.00167 minutes
= 0.01837 minutes

Step 4: Convert the standard time to minutes
To convert the standard time to minutes, we round the value to two decimal places:

Standard time = 0.01837 minutes (rounded to 2 decimal places)
= 0.02 minutes
= 2.64 minutes

Therefore, the standard time of the operation is 2.64 minutes, which corresponds to option C.
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A stop watch time study on an operator with a performance rating of 120 yielded a time of 2 minute. If allowances of 10% of the total available time are to be given, the standard time of the operation is:a)2 minutesb)2.4 minutes c)2.64 minutes d)2.67 minutesCorrect answer is option 'C'. Can you explain this answer?
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