Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > (Q1-Q.6) An amplifier is measured to have an ...
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(Q1-Q.6) An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ, then
Q. Find Gm.
- a)1 A/V
- b)10 A/V
- c)100 A/V
- d)1000 A/V
Correct answer is option 'A'. Can you explain this answer?
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(Q1-Q.6) An amplifier is measured to have an internal resistance of 10...
Gm = (voltage gain in V/V) / (output resistance) or 100/100 A/V.
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(Q1-Q.6) An amplifier is measured to have an internal resistance of 10...
Understanding the Problem
To find the transconductance (Gm) of the amplifier, we start with the given parameters:
- Internal resistance (Rin) = 10 kΩ
- Voltage gain (Av) = 100 V/V
- Output resistance (Rout) = 100 Ω
- Load resistance (Rl) = 1 kΩ
- Source resistance (Rs) = 2 kΩ
The overall output resistance when a load is connected is given as 8 kΩ.
Calculating Gm
Transconductance (Gm) can be defined as the change in output current (Io) per unit change in input voltage (Vin):
- \( Gm = \frac{Io}{Vin} \)
To find Gm, we need to calculate the output current (Io) when the amplifier is driven by the input voltage (Vin).
Step 1: Calculate Output Voltage (Vo)
Using the voltage gain:
- \( Vo = Av \times Vin = 100 \times Vin \)
Step 2: Calculate Output Current (Io)
The output current can be calculated using Ohm's law:
- \( Io = \frac{Vo}{Rout} = \frac{100 \times Vin}{100} = Vin \)
Step 3: Find Gm
Now substituting Io into the Gm equation:
- \( Gm = \frac{Vin}{Vin} = 1 A/V \)
Conclusion
Thus, the transconductance Gm is:
- **1 A/V**, which corresponds to option **A**.
This result indicates that for every 1V change in input voltage, the output current changes by 1A, confirming the correctness of option A.
To find the transconductance (Gm) of the amplifier, we start with the given parameters:
- Internal resistance (Rin) = 10 kΩ
- Voltage gain (Av) = 100 V/V
- Output resistance (Rout) = 100 Ω
- Load resistance (Rl) = 1 kΩ
- Source resistance (Rs) = 2 kΩ
The overall output resistance when a load is connected is given as 8 kΩ.
Calculating Gm
Transconductance (Gm) can be defined as the change in output current (Io) per unit change in input voltage (Vin):
- \( Gm = \frac{Io}{Vin} \)
To find Gm, we need to calculate the output current (Io) when the amplifier is driven by the input voltage (Vin).
Step 1: Calculate Output Voltage (Vo)
Using the voltage gain:
- \( Vo = Av \times Vin = 100 \times Vin \)
Step 2: Calculate Output Current (Io)
The output current can be calculated using Ohm's law:
- \( Io = \frac{Vo}{Rout} = \frac{100 \times Vin}{100} = Vin \)
Step 3: Find Gm
Now substituting Io into the Gm equation:
- \( Gm = \frac{Vin}{Vin} = 1 A/V \)
Conclusion
Thus, the transconductance Gm is:
- **1 A/V**, which corresponds to option **A**.
This result indicates that for every 1V change in input voltage, the output current changes by 1A, confirming the correctness of option A.
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(Q1-Q.6) An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ, thenQ. Find Gm.a)1 A/Vb)10 A/Vc)100 A/Vd)1000 A/VCorrect answer is option 'A'. Can you explain this answer?
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(Q1-Q.6) An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ, thenQ. Find Gm.a)1 A/Vb)10 A/Vc)100 A/Vd)1000 A/VCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about (Q1-Q.6) An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ, thenQ. Find Gm.a)1 A/Vb)10 A/Vc)100 A/Vd)1000 A/VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (Q1-Q.6) An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ, thenQ. Find Gm.a)1 A/Vb)10 A/Vc)100 A/Vd)1000 A/VCorrect answer is option 'A'. Can you explain this answer?.
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