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A series resonant circuit has an inductor L = 10 mH.The resonant frequency ωo = 106 rad/s and bandwidth is BW = 103 rad/s. The value of R and C will be
  • a)
    100 μF, 10Ω
  • b)
    100 pF, 10Ω
  • c)
    100 pF, 10 MΩ
  • d)
    100 μF, 10 MΩ
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A series resonant circuit has an inductor L =10 mH.The resonant freque...

 = 100pF
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A series resonant circuit has an inductor L =10 mH.The resonant freque...

 = 100pF
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A series resonant circuit has an inductor L =10 mH.The resonant freque...

 = 100pF
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A series resonant circuit has an inductor L =10 mH.The resonant frequency ωo=106 rad/s and bandwidth is BW = 103 rad/s. The value of R and C will bea)100 μF, 10Ωb)100 pF, 10Ωc)100 pF, 10 MΩd)100 μF, 10 MΩCorrect answer is option 'B'. Can you explain this answer?
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A series resonant circuit has an inductor L =10 mH.The resonant frequency ωo=106 rad/s and bandwidth is BW = 103 rad/s. The value of R and C will bea)100 μF, 10Ωb)100 pF, 10Ωc)100 pF, 10 MΩd)100 μF, 10 MΩCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A series resonant circuit has an inductor L =10 mH.The resonant frequency ωo=106 rad/s and bandwidth is BW = 103 rad/s. The value of R and C will bea)100 μF, 10Ωb)100 pF, 10Ωc)100 pF, 10 MΩd)100 μF, 10 MΩCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A series resonant circuit has an inductor L =10 mH.The resonant frequency ωo=106 rad/s and bandwidth is BW = 103 rad/s. The value of R and C will bea)100 μF, 10Ωb)100 pF, 10Ωc)100 pF, 10 MΩd)100 μF, 10 MΩCorrect answer is option 'B'. Can you explain this answer?.
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