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A bullet of mass 10gm is fired horizontally in the north direction with a velocity of 500m/sec at 300N latitude and it hits a target 250 meters away. Then
- a)The coriolis acceleration is 0.036 m/sec2 towards west.
- b)Time of journey t = 0.5sec
- c)Deflection of the cullet due to the coriolis acceleration 4.5 x 10-3m
- d)Certical displacement of the bullet due to gravity is 1.23m
Correct answer is option 'A,B,C,D'. Can you explain this answer?
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Verified Answer
A bullet of mass 10gm is fired horizontally in the north direction wit...
If X-axis is taken vertically, Z-axis towards north and Y-axis along east, then the velocity of the bullet is v = 500 km/sec. and angular velocity - UTP2 
because the angular velocity vector ww of the earth is directed parallel to its axis and is inclined at 300 to the horizibtal.
Hence coriolis acceleration
Time of journey, t
Deflection of the bullet due to the coriolis acceleration
Vertical displacement of the bulet due to the gravity
Coriolis force = -2m w x v
=3.6 x 10-4 newton towwards east.
because the angular velocity vector ww of the earth is directed parallel to its axis and is inclined at 300 to the horizibtal.Hence coriolis acceleration
Time of journey, t
Deflection of the bullet due to the coriolis acceleration
Vertical displacement of the bulet due to the gravity
Coriolis force = -2m w x v
=3.6 x 10-4 newton towwards east.
Most Upvoted Answer
A bullet of mass 10gm is fired horizontally in the north direction wit...
Coriolis Effect
The Coriolis effect is the apparent deflection of the path of a moving object caused by the rotation of the Earth. It is an important concept in physics and is particularly relevant in the case of projectiles or objects moving long distances.
Given:
Mass of the bullet, m = 10 gm = 0.01 kg
Velocity of the bullet, v = 500 m/s
Latitude, θ = 300N
Distance traveled, d = 250 m
Now let's analyze the given statements one by one.
a) The Coriolis acceleration is 0.036 m/s² towards the west.
The Coriolis acceleration, aC, can be calculated using the formula:
aC = 2 * v * ω * sin(θ)
where ω is the angular velocity of the Earth, given by:
ω = 2π / T
T is the period of rotation of the Earth, which is approximately 24 hours or 86400 seconds.
Substituting the given values, we can calculate the Coriolis acceleration:
ω = 2π / 86400 s ≈ 7.27 × 10⁻⁵ rad/s
θ = 30° = π / 6 rad
aC = 2 * 500 m/s * 7.27 × 10⁻⁵ rad/s * sin(π / 6) ≈ 0.036 m/s²
Therefore, the statement is correct.
b) The time of journey, t = 0.5 sec.
The time of journey can be calculated using the formula:
t = d / v
Substituting the given values, we get:
t = 250 m / 500 m/s = 0.5 sec
Therefore, the statement is correct.
c) The deflection of the bullet due to the Coriolis acceleration is 4.5 × 10⁻³ m.
The deflection of the bullet, Δx, can be calculated using the formula:
Δx = (1/2) * aC * t²
Substituting the given values, we get:
Δx = (1/2) * 0.036 m/s² * (0.5 sec)² ≈ 4.5 × 10⁻³ m
Therefore, the statement is correct.
d) The vertical displacement of the bullet due to gravity is 1.23 m.
The vertical displacement of the bullet, Δy, due to gravity can be calculated using the formula:
Δy = (1/2) * g * t²
where g is the acceleration due to gravity, approximately 9.8 m/s².
Substituting the given values, we get:
Δy = (1/2) * 9.8 m/s² * (0.5 sec)² ≈ 1.23 m
Therefore, the statement is correct.
In conclusion, all the given statements are correct.
The Coriolis effect is the apparent deflection of the path of a moving object caused by the rotation of the Earth. It is an important concept in physics and is particularly relevant in the case of projectiles or objects moving long distances.
Given:
Mass of the bullet, m = 10 gm = 0.01 kg
Velocity of the bullet, v = 500 m/s
Latitude, θ = 300N
Distance traveled, d = 250 m
Now let's analyze the given statements one by one.
a) The Coriolis acceleration is 0.036 m/s² towards the west.
The Coriolis acceleration, aC, can be calculated using the formula:
aC = 2 * v * ω * sin(θ)
where ω is the angular velocity of the Earth, given by:
ω = 2π / T
T is the period of rotation of the Earth, which is approximately 24 hours or 86400 seconds.
Substituting the given values, we can calculate the Coriolis acceleration:
ω = 2π / 86400 s ≈ 7.27 × 10⁻⁵ rad/s
θ = 30° = π / 6 rad
aC = 2 * 500 m/s * 7.27 × 10⁻⁵ rad/s * sin(π / 6) ≈ 0.036 m/s²
Therefore, the statement is correct.
b) The time of journey, t = 0.5 sec.
The time of journey can be calculated using the formula:
t = d / v
Substituting the given values, we get:
t = 250 m / 500 m/s = 0.5 sec
Therefore, the statement is correct.
c) The deflection of the bullet due to the Coriolis acceleration is 4.5 × 10⁻³ m.
The deflection of the bullet, Δx, can be calculated using the formula:
Δx = (1/2) * aC * t²
Substituting the given values, we get:
Δx = (1/2) * 0.036 m/s² * (0.5 sec)² ≈ 4.5 × 10⁻³ m
Therefore, the statement is correct.
d) The vertical displacement of the bullet due to gravity is 1.23 m.
The vertical displacement of the bullet, Δy, due to gravity can be calculated using the formula:
Δy = (1/2) * g * t²
where g is the acceleration due to gravity, approximately 9.8 m/s².
Substituting the given values, we get:
Δy = (1/2) * 9.8 m/s² * (0.5 sec)² ≈ 1.23 m
Therefore, the statement is correct.
In conclusion, all the given statements are correct.
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A bullet of mass 10gm is fired horizontally in the north direction with a velocity of 500m/sec at 300N latitude and it hits a target 250 meters away. Thena)The coriolis acceleration is 0.036 m/sec2 towards west.b)Time of journey t = 0.5secc)Deflection of the cullet due to the coriolis acceleration 4.5 x 10-3md)Certical displacement of the bullet due to gravity is 1.23mCorrect answer is option 'A,B,C,D'. Can you explain this answer?
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A bullet of mass 10gm is fired horizontally in the north direction with a velocity of 500m/sec at 300N latitude and it hits a target 250 meters away. Thena)The coriolis acceleration is 0.036 m/sec2 towards west.b)Time of journey t = 0.5secc)Deflection of the cullet due to the coriolis acceleration 4.5 x 10-3md)Certical displacement of the bullet due to gravity is 1.23mCorrect answer is option 'A,B,C,D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A bullet of mass 10gm is fired horizontally in the north direction with a velocity of 500m/sec at 300N latitude and it hits a target 250 meters away. Thena)The coriolis acceleration is 0.036 m/sec2 towards west.b)Time of journey t = 0.5secc)Deflection of the cullet due to the coriolis acceleration 4.5 x 10-3md)Certical displacement of the bullet due to gravity is 1.23mCorrect answer is option 'A,B,C,D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 10gm is fired horizontally in the north direction with a velocity of 500m/sec at 300N latitude and it hits a target 250 meters away. Thena)The coriolis acceleration is 0.036 m/sec2 towards west.b)Time of journey t = 0.5secc)Deflection of the cullet due to the coriolis acceleration 4.5 x 10-3md)Certical displacement of the bullet due to gravity is 1.23mCorrect answer is option 'A,B,C,D'. Can you explain this answer?.
A bullet of mass 10gm is fired horizontally in the north direction with a velocity of 500m/sec at 300N latitude and it hits a target 250 meters away. Thena)The coriolis acceleration is 0.036 m/sec2 towards west.b)Time of journey t = 0.5secc)Deflection of the cullet due to the coriolis acceleration 4.5 x 10-3md)Certical displacement of the bullet due to gravity is 1.23mCorrect answer is option 'A,B,C,D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A bullet of mass 10gm is fired horizontally in the north direction with a velocity of 500m/sec at 300N latitude and it hits a target 250 meters away. Thena)The coriolis acceleration is 0.036 m/sec2 towards west.b)Time of journey t = 0.5secc)Deflection of the cullet due to the coriolis acceleration 4.5 x 10-3md)Certical displacement of the bullet due to gravity is 1.23mCorrect answer is option 'A,B,C,D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 10gm is fired horizontally in the north direction with a velocity of 500m/sec at 300N latitude and it hits a target 250 meters away. Thena)The coriolis acceleration is 0.036 m/sec2 towards west.b)Time of journey t = 0.5secc)Deflection of the cullet due to the coriolis acceleration 4.5 x 10-3md)Certical displacement of the bullet due to gravity is 1.23mCorrect answer is option 'A,B,C,D'. Can you explain this answer?.
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