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A program attempts to generate as many permutations as possible of the string, 'abcd' by pushing the characters in the same order onto a stack, but it may pop off the top character at any time. Which one of the following strings CANNOT be generated using this program?
- a)abcd
- b)dcba
- c)cbad
- d)cabd
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A program attempts to generate as many permutations as possible of the...
A. push a & pop a, push b & pop b, push c & pop c, and finally push d and pop d
sequence of popped elements will come to abcd
B. first push abcd, and after that pop one by one sequence of popped elements will come to dcba
C. push abc, and after that pop one by one sequence of popped elements will come to cba, now push d and pop d, final
sequence comes to cbad
D. this sequence is not possible because 'a' can not be pooped before 'b' any how
sequence of popped elements will come to abcd
B. first push abcd, and after that pop one by one sequence of popped elements will come to dcba
C. push abc, and after that pop one by one sequence of popped elements will come to cba, now push d and pop d, final
sequence comes to cbad
D. this sequence is not possible because 'a' can not be pooped before 'b' any how
Most Upvoted Answer
A program attempts to generate as many permutations as possible of the...
Explanation:
To generate permutations of the string "abcd" using a stack, we can follow these steps:
1. Start with an empty stack.
2. Push the characters of the string "abcd" onto the stack in the same order.
3. At any point, we can choose to either pop the top character from the stack or leave it on the stack.
4. Repeat steps 3 for all possible combinations until the stack is empty.
Permutations:
Let's analyze the given options to determine which one cannot be generated using the described program.
Option A: abcdb
- We can generate this permutation by pushing "a", "b", "c", "d" onto the stack and popping "b" from the top of the stack.
- Steps: push a, push b, push c, push d, pop b.
Option B: dcba
- We can generate this permutation by pushing "d", "c", "b", "a" onto the stack and popping "d", "c", "b" from the top of the stack.
- Steps: push d, push c, push b, push a, pop d, pop c, pop b.
Option C: cbad
- We can generate this permutation by pushing "c", "b", "a", "d" onto the stack and popping "b" from the top of the stack.
- Steps: push c, push b, push a, push d, pop b.
Option D: cabd
- This permutation cannot be generated using the described program because the character "c" is pushed onto the stack before the character "a".
- Since we can only pop the top character from the stack, it is not possible to change the order of the characters on the stack.
- Therefore, the program cannot generate the permutation "cabd".
Conclusion:
The string "cabd" cannot be generated using the program that pushes the characters of the string "abcd" onto a stack and allows popping the top character at any time.
To generate permutations of the string "abcd" using a stack, we can follow these steps:
1. Start with an empty stack.
2. Push the characters of the string "abcd" onto the stack in the same order.
3. At any point, we can choose to either pop the top character from the stack or leave it on the stack.
4. Repeat steps 3 for all possible combinations until the stack is empty.
Permutations:
Let's analyze the given options to determine which one cannot be generated using the described program.
Option A: abcdb
- We can generate this permutation by pushing "a", "b", "c", "d" onto the stack and popping "b" from the top of the stack.
- Steps: push a, push b, push c, push d, pop b.
Option B: dcba
- We can generate this permutation by pushing "d", "c", "b", "a" onto the stack and popping "d", "c", "b" from the top of the stack.
- Steps: push d, push c, push b, push a, pop d, pop c, pop b.
Option C: cbad
- We can generate this permutation by pushing "c", "b", "a", "d" onto the stack and popping "b" from the top of the stack.
- Steps: push c, push b, push a, push d, pop b.
Option D: cabd
- This permutation cannot be generated using the described program because the character "c" is pushed onto the stack before the character "a".
- Since we can only pop the top character from the stack, it is not possible to change the order of the characters on the stack.
- Therefore, the program cannot generate the permutation "cabd".
Conclusion:
The string "cabd" cannot be generated using the program that pushes the characters of the string "abcd" onto a stack and allows popping the top character at any time.
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