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A program attempts to generate as many permutations as possible of the string, ‘abcd' by pushing the characters a, b, c, d in the same order onto a stack, but it may pop off the top character at any time. Which one of the following strings CANNOT be generated using this program?
- a)abed
- b)deba
- c)ebad
- d)cabd
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A program attempts to generate as many permutations as possible of the...
• For every element push an element and pop immediately i.e. push (a) then pop will give permutation abed.
• For all elements push (a), push (b), push (c) and push (d) then pop, pop, pop, pop will give us deba.
• Push (a), push (b), push (c) then pop, pop, pop will give is eba, then push (d) and pop will gives us deba.
• Option (d) is not possible because a cannot pop after c and before ‘b’.
• For all elements push (a), push (b), push (c) and push (d) then pop, pop, pop, pop will give us deba.
• Push (a), push (b), push (c) then pop, pop, pop will give is eba, then push (d) and pop will gives us deba.
• Option (d) is not possible because a cannot pop after c and before ‘b’.
Most Upvoted Answer
A program attempts to generate as many permutations as possible of the...
Explanation:
Permutations:
- The program pushes the characters 'a', 'b', 'c', 'd' onto the stack in the order they appear in the string 'abcd'.
- At any point, the program can pop off the top character from the stack.
Given Strings:
1. abed
2. debac
3. ebadd
4. cabd
Analysis:
- To generate the given strings, the program must follow the order of characters in the original string 'abcd'.
- Let's analyze each string:
1. abed: This string can be generated by pushing 'a', 'b', 'e' onto the stack, and then popping 'e' before pushing 'd'.
2. debac: This string can be generated by pushing 'd', 'e', 'b', 'a' onto the stack in order.
3. ebadd: This string can be generated by pushing 'e', 'b', 'a', 'd', 'd' onto the stack.
4. cabd: This string cannot be generated because after pushing 'c', 'a', 'b' onto the stack, the next character should be 'd' according to the original string 'abcd'. However, 'a' is popped off before 'd' is pushed.
Therefore, the string cabd cannot be generated using the given program.
Permutations:
- The program pushes the characters 'a', 'b', 'c', 'd' onto the stack in the order they appear in the string 'abcd'.
- At any point, the program can pop off the top character from the stack.
Given Strings:
1. abed
2. debac
3. ebadd
4. cabd
Analysis:
- To generate the given strings, the program must follow the order of characters in the original string 'abcd'.
- Let's analyze each string:
1. abed: This string can be generated by pushing 'a', 'b', 'e' onto the stack, and then popping 'e' before pushing 'd'.
2. debac: This string can be generated by pushing 'd', 'e', 'b', 'a' onto the stack in order.
3. ebadd: This string can be generated by pushing 'e', 'b', 'a', 'd', 'd' onto the stack.
4. cabd: This string cannot be generated because after pushing 'c', 'a', 'b' onto the stack, the next character should be 'd' according to the original string 'abcd'. However, 'a' is popped off before 'd' is pushed.
Therefore, the string cabd cannot be generated using the given program.
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