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An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________
Correct answer is '(312.8)'. Can you explain this answer?
Verified Answer
An aircraft approaches the threshold of a runway strip at a speed of 2...
Speed of aircraft, μ = 200 km/hr
Deceleration of aircraft on the runway Aircraft takes 18 sec to exit the runway strip.
Speed of the aircraft at the exit of the runway
uf = ui+ at
= 55.56 - 1.697 x18 = 25.014 m/s
After runway aircraft decelerate with Total distance travelled by the aircraft from the location of exit on the runway
U2 = u2 + 2aS
0 = 25.0142 - 2 x1 x S
S = 312.8 m
Deceleration of aircraft on the runway Aircraft takes 18 sec to exit the runway strip.
Speed of the aircraft at the exit of the runway
uf = ui+ at
= 55.56 - 1.697 x18 = 25.014 m/s
After runway aircraft decelerate with Total distance travelled by the aircraft from the location of exit on the runway
U2 = u2 + 2aS
0 = 25.0142 - 2 x1 x S
S = 312.8 m
Most Upvoted Answer
An aircraft approaches the threshold of a runway strip at a speed of 2...
To find the distance of the gate position from the location of exit on the runway, we can break down the problem into two parts:
1. Calculating the distance covered during the deceleration on the runway strip.
2. Calculating the distance covered after exiting the runway.
1. Calculating the distance covered during the deceleration on the runway strip:
Given:
Initial speed (u) = 200 km/h = 200 * (1000/3600) m/s = 55.6 m/s
Deceleration (a) = -1.697 m/s^2 (negative sign indicates deceleration)
Using the equation of motion, v^2 = u^2 - 2as, where v is the final velocity:
0 = (55.6)^2 - 2 * (-1.697) * s1
Solving this equation will give us the distance covered during deceleration on the runway strip, denoted as s1.
2. Calculating the distance covered after exiting the runway:
Given:
Deceleration (a) = -1 m/s^2 (negative sign indicates deceleration)
Time taken (t) = 18 s
Using the equation of motion, s = ut + (1/2)at^2, where u is the initial velocity:
s2 = 0 + (1/2) * (-1) * (18)^2
Solving this equation will give us the distance covered after exiting the runway, denoted as s2.
3. Calculating the total distance:
Total distance = s1 + s2
Now, let's calculate the values:
1. Calculating the distance covered during the deceleration on the runway strip (s1):
0 = (55.6)^2 - 2 * (-1.697) * s1
s1 = (55.6)^2 / (2 * 1.697)
s1 ≈ 962.72 m
2. Calculating the distance covered after exiting the runway (s2):
s2 = (1/2) * (-1) * (18)^2
s2 = 162 m
3. Calculating the total distance:
Total distance = s1 + s2
Total distance = 962.72 + 162
Total distance ≈ 1124.72 m
Therefore, the distance of the gate position from the location of exit on the runway is approximately 1124.72 m.
1. Calculating the distance covered during the deceleration on the runway strip.
2. Calculating the distance covered after exiting the runway.
1. Calculating the distance covered during the deceleration on the runway strip:
Given:
Initial speed (u) = 200 km/h = 200 * (1000/3600) m/s = 55.6 m/s
Deceleration (a) = -1.697 m/s^2 (negative sign indicates deceleration)
Using the equation of motion, v^2 = u^2 - 2as, where v is the final velocity:
0 = (55.6)^2 - 2 * (-1.697) * s1
Solving this equation will give us the distance covered during deceleration on the runway strip, denoted as s1.
2. Calculating the distance covered after exiting the runway:
Given:
Deceleration (a) = -1 m/s^2 (negative sign indicates deceleration)
Time taken (t) = 18 s
Using the equation of motion, s = ut + (1/2)at^2, where u is the initial velocity:
s2 = 0 + (1/2) * (-1) * (18)^2
Solving this equation will give us the distance covered after exiting the runway, denoted as s2.
3. Calculating the total distance:
Total distance = s1 + s2
Now, let's calculate the values:
1. Calculating the distance covered during the deceleration on the runway strip (s1):
0 = (55.6)^2 - 2 * (-1.697) * s1
s1 = (55.6)^2 / (2 * 1.697)
s1 ≈ 962.72 m
2. Calculating the distance covered after exiting the runway (s2):
s2 = (1/2) * (-1) * (18)^2
s2 = 162 m
3. Calculating the total distance:
Total distance = s1 + s2
Total distance = 962.72 + 162
Total distance ≈ 1124.72 m
Therefore, the distance of the gate position from the location of exit on the runway is approximately 1124.72 m.
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An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer?
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An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer?.
An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer?.
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An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer?, a detailed solution for An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer? has been provided alongside types of An aircraft approaches the threshold of a runway strip at a speed of 200 km/h. The pilot decelerates the aircraft at a rate of 1.697 m/s2 and takes 18 s to exit the runway strip. If the deceleration after exiting the runway is 1 m/s2, then the distance (in m, up to one decimal place) of the gate position from the location of exit on the runway is ____________Correct answer is '(312.8)'. Can you explain this answer? theory, EduRev gives you an
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