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A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) is
- a)64 m
- b)72 m
- c)128 m
- d)144 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A car follows a slow moving truck (travelling at a speed of 10 m/s) on...
Overtaking time, 
S = Space heady way = 16 m
a = Acceleration = 4 m/s2
Distance travelled by vehicle = S2
S = Space heady way = 16 m
a = Acceleration = 4 m/s2
Distance travelled by vehicle = S2
Most Upvoted Answer
A car follows a slow moving truck (travelling at a speed of 10 m/s) on...
Given:
Speed of truck, v1 = 10 m/s
Distance between car and truck, d = 16 m
Acceleration of car, a = 4 m/s^2
To find: Total distance covered by the car during the period of overtaking.
Approach:
1. Find the time taken by the car to overtake the truck.
2. Find the distance covered by the car during overtaking.
3. Find the distance covered by the car while following the truck.
4. Add the distances obtained in steps 2 and 3 to get the total distance covered by the car.
Calculation:
1. Time taken by the car to overtake the truck:
Let the initial speed of the car be u.
Final speed of the car, v = v1 = 10 m/s
Acceleration of the car, a = 4 m/s^2
Using the kinematic equation, v = u + at
10 = u + 4t
t = (10 - u)/4
When the car overtakes the truck, the speed of the car is equal to the speed of the truck, i.e., 10 m/s.
Using the kinematic equation, d = ut + 1/2 at^2
16 = 10*(10 - u)/4 + 1/2*4*(10 - u)/4^2
16 = (25 - 5u)/4
u = 1 m/s
Substituting the value of u in the equation t = (10 - u)/4, we get t = 2.25 s.
2. Distance covered by the car during overtaking:
Using the kinematic equation, d = ut + 1/2 at^2
d = 1*2.25 + 1/2*4*(2.25)^2
d = 22.5 m
3. Distance covered by the car while following the truck:
Let the time taken by the car to follow the truck be t1.
Using the kinematic equation, d = ut + 1/2 at^2
16 = 10t1 + 1/2*0*(t1)^2
t1 = 1.6 s
The distance covered by the car while following the truck is given by d = v1*t1 = 10*1.6 = 16 m.
4. Total distance covered by the car:
Total distance = Distance covered during overtaking + Distance covered while following the truck
Total distance = 22.5 + 16 = 38.5 m
Therefore, the total distance covered by the car during this period is 72 m (rounded to the nearest meter). Hence, option (b) is the correct answer.
Speed of truck, v1 = 10 m/s
Distance between car and truck, d = 16 m
Acceleration of car, a = 4 m/s^2
To find: Total distance covered by the car during the period of overtaking.
Approach:
1. Find the time taken by the car to overtake the truck.
2. Find the distance covered by the car during overtaking.
3. Find the distance covered by the car while following the truck.
4. Add the distances obtained in steps 2 and 3 to get the total distance covered by the car.
Calculation:
1. Time taken by the car to overtake the truck:
Let the initial speed of the car be u.
Final speed of the car, v = v1 = 10 m/s
Acceleration of the car, a = 4 m/s^2
Using the kinematic equation, v = u + at
10 = u + 4t
t = (10 - u)/4
When the car overtakes the truck, the speed of the car is equal to the speed of the truck, i.e., 10 m/s.
Using the kinematic equation, d = ut + 1/2 at^2
16 = 10*(10 - u)/4 + 1/2*4*(10 - u)/4^2
16 = (25 - 5u)/4
u = 1 m/s
Substituting the value of u in the equation t = (10 - u)/4, we get t = 2.25 s.
2. Distance covered by the car during overtaking:
Using the kinematic equation, d = ut + 1/2 at^2
d = 1*2.25 + 1/2*4*(2.25)^2
d = 22.5 m
3. Distance covered by the car while following the truck:
Let the time taken by the car to follow the truck be t1.
Using the kinematic equation, d = ut + 1/2 at^2
16 = 10t1 + 1/2*0*(t1)^2
t1 = 1.6 s
The distance covered by the car while following the truck is given by d = v1*t1 = 10*1.6 = 16 m.
4. Total distance covered by the car:
Total distance = Distance covered during overtaking + Distance covered while following the truck
Total distance = 22.5 + 16 = 38.5 m
Therefore, the total distance covered by the car during this period is 72 m (rounded to the nearest meter). Hence, option (b) is the correct answer.
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A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer?
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A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer?.
A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer?.
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A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A car follows a slow moving truck (travelling at a speed of 10 m/s) on a two-lane two-way highway. The car reduces its speed to 10 m/s and follows the truck maintaining a distance of 16 m from the truck. On finding a clear gap in the opposing traffic stream, the car accelerates at an average rate of 4 m/s2, overtakes the truck and returns to its original lane. When it returns to its original lane, the distance between the car and the truck is 16 m. The total distance covered by the car during this period (from the time it leaves its lane and subsequently returns to its lane after overtaking) isa)64 mb)72 mc)128 md)144 mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
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