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The overtaking sight distance required on a highway is 250 m. The required clearance of obstruction (in meters, up to two decimal place) from centre line of a circular curve of radius 350 m and length 180 m is ________. (Assume two lane highway with d = 1.9 m.)
    Correct answer is between '22.2,22.6'. Can you explain this answer?
    Verified Answer
    The overtaking sight distance required on a highway is 250 m. The requ...
    Concept:
    Since length of circular curve (Lc) < sight distance (SSD, ISD, OSD)
    Therefore, set-back distance, for two lane road,
    From centre line of the road or centre line of circular curve.
    Where R = radius of the curve
    S = sight distance
    Lc = length of the curve
    ∝ = angle between segment of the curve.
    Calculation:
    Given:
    OSD = 250 m, d = 1.9 m
    R = 350 m
    Lc = 180 m.
    Also,
    ∴ setback distance or the required clearance of obstruction from the centre line of road on circular curve,
    M = 350−(350−1.9)×cos(14.814)
    M = 350 – 336.53 + 8.95
    M = 22.42 m
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    The overtaking sight distance required on a highway is 250 m. The requ...
    Calculation of Overtaking Sight Distance:
    The overtaking sight distance is the distance required for a driver to overtake another vehicle safely on a highway. It includes the distance required for the driver to see any oncoming vehicles and also to accelerate and complete the overtaking maneuver.

    Components of Overtaking Sight Distance:
    The overtaking sight distance consists of three main components:
    1. Distance required for the driver to perceive and react to a potential hazard (d1)
    2. Distance required for the driver to accelerate and overtake the slower vehicle (d2)
    3. Distance required for the driver to return to the original lane safely (d3)

    Calculation of d1:
    The distance required for the driver to perceive and react to a potential hazard can be calculated using the formula:
    d1 = 1/2 * V * T

    Where:
    V = design speed of the highway (in m/s)
    T = perception and reaction time of the driver (in seconds)

    Calculation of d2:
    The distance required for the driver to accelerate and overtake the slower vehicle can be calculated using the formula:
    d2 = (V^2 - V0^2) / (2 * a)

    Where:
    V = design speed of the highway (in m/s)
    V0 = initial speed of the overtaking vehicle (in m/s)
    a = acceleration of the overtaking vehicle (in m/s^2)

    Calculation of d3:
    The distance required for the driver to return to the original lane safely can be calculated using the formula:
    d3 = 1/2 * V * T

    Where:
    V = design speed of the highway (in m/s)
    T = perception and reaction time of the driver (in seconds)

    Calculation of Overtaking Sight Distance:
    The overtaking sight distance (D) is the sum of d1, d2, and d3:
    D = d1 + d2 + d3

    Calculation of Clearance of Obstruction:
    To calculate the required clearance of an obstruction from the center line of a circular curve, we need to consider the horizontal and vertical dimensions.

    Horizontal Clearance:
    The horizontal clearance is the distance between the center line of the circular curve and the obstruction. It can be calculated using the formula:
    Horizontal Clearance = Radius of the Curve - (Width of Lane + Design Offset)

    Where:
    Radius of the Curve = radius of the circular curve (in meters)
    Width of Lane = width of the lane (in meters)
    Design Offset = offset distance from the center line to the edge of the lane (in meters)

    Vertical Clearance:
    The vertical clearance is the distance between the highest point of the obstruction and the highest point of the vehicle. It should be sufficient to allow the vehicle to pass safely without any obstructions.

    Final Calculation:
    To find the required clearance of the obstruction, we need to consider both the horizontal and vertical dimensions. The final required clearance will be the maximum of the horizontal and vertical clearances.

    By calculating the horizontal and vertical clearances and taking the maximum value, we can determine the required clearance of the obstruction from the center line of the circular curve.

    Given the radius of the circular curve (350 m), length of the curve (180 m), and width of the lane (1.9
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    The overtaking sight distance required on a highway is 250 m. The required clearance of obstruction (in meters, up to two decimal place) from centre line of a circular curve of radius 350 m and length 180 m is ________. (Assume two lane highway with d = 1.9 m.)Correct answer is between '22.2,22.6'. Can you explain this answer?
    Question Description
    The overtaking sight distance required on a highway is 250 m. The required clearance of obstruction (in meters, up to two decimal place) from centre line of a circular curve of radius 350 m and length 180 m is ________. (Assume two lane highway with d = 1.9 m.)Correct answer is between '22.2,22.6'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The overtaking sight distance required on a highway is 250 m. The required clearance of obstruction (in meters, up to two decimal place) from centre line of a circular curve of radius 350 m and length 180 m is ________. (Assume two lane highway with d = 1.9 m.)Correct answer is between '22.2,22.6'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The overtaking sight distance required on a highway is 250 m. The required clearance of obstruction (in meters, up to two decimal place) from centre line of a circular curve of radius 350 m and length 180 m is ________. (Assume two lane highway with d = 1.9 m.)Correct answer is between '22.2,22.6'. Can you explain this answer?.
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