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A DC-DC buck converter operates in continuous conduction mode. It has 48 V input voltage, and it feeds a resistive load of 24 Ω. The switching frequency of the converter is 250 Hz. If switch-on duration is 1 ms, the load power is
  • a)
    12 W
  • b)
    6 W
  • c)
    24 W
  • d)
    48 W
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A DC-DC buck converter operates in continuous conduction mode. It has ...
Given that
Switch frequency, fs = 250Hz
Load resistance RL = 24Ω
Supply voltage Vs = 48V
TON = 1 msec

P = 6 watts 
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Most Upvoted Answer
A DC-DC buck converter operates in continuous conduction mode. It has ...
Ω. The converter has a duty cycle of 0.5. Calculate the output voltage and output current of the buck converter.

To calculate the output voltage of the buck converter, we can use the formula:

Vout = Vin * D

where Vin is the input voltage and D is the duty cycle.

Vout = 48 V * 0.5 = 24 V

Therefore, the output voltage of the buck converter is 24 V.

To calculate the output current, we can use the formula:

Iout = Vin / R

where Vin is the input voltage and R is the load resistance.

Iout = 48 V / 24 Ω = 2 A

Therefore, the output current of the buck converter is 2 A.
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